|
Author |
Message |
|
TAGS:
|
|
|
GMAT Pill Instructor
Joined: 14 Apr 2009
Posts: 918
Location: New York, NY
Followers: 87
Kudos [?]:
228
[0], given: 0
|
A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
 16 Nov 2012, 07:38
Question Stats:
85% (02:04) correct
14% (00:27) wrong based on 21 sessions
A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created? A) 140 B) 320 C) 560 D) 700 E) 840 For those of you studying Combinations and Probability, we've posted a free lesson on combinations here: http://www.gmatpill.com/gmat-practice-t ... ons-lesson.png) The video explanation for the above question is at 22:13 Part 1: Combination Framework - Dice, Marbles, Pocket Pair" Part 2: Apply to GMAT - Word Problems Part 3: Poker Probability - Pocket Pair vs Pocket Aces, Flush/Full House 00:00 - Intro 01:00 - Warmup 02:12 - Part 1 Overview: Combinations & Permutations vs Variations 08:35 - Part 1 Details: Picking Teams, Dice, Pocket Pair, Dating 17:21 - Part 2: Apply to GMAT - Word Problem #1 22:13 - Part 2: Apply to GMAT - Word Problem #2 31:34 - Part 2: Apply to GMAT - Word Problem #3 38:04 - Part 3: Poker Probability - Pocket Pair vs Pocket Aces 43:40 - Part 3: Poker Probability - Given Pocket Aces, 3-of-a-Kind? 46:13 - Part 3: Poker Probability - 1-Pair by 5th Flop 49:59 - Part 3: Poker Probability - Full House/Flush 1:00:00 - Conclusion
_________________
      
... and more
Zeke Lee, GMAT Pill Study Method (Study Less. Score More.) | Download Ebook
- How A McKinsey Analyst Struggled with GMAT for 2 Yrs
- GMAT Score From 650 to 760 + 25 Minutes left on the exam! Wow!
GMAT Pill Reviews
|
|
|
|
|
|
|
|
|
Director
Status: Disappointed devil..
Joined: 15 Sep 2012
Posts: 591
Location: India
Concentration: Strategy, General Management
WE: Information Technology (Computer Software)
Followers: 20
Kudos [?]:
230
[3] , given: 23
|
Re: Cooking Team Combinations [#permalink]
16 Nov 2012, 08:14
3
This post received
KUDOS
gmatpill wrote: A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A) 140
B) 320
C) 560
D) 700
E) 840
Only possible combinations are a team of 2M, 4 W or 3M,3W. Possible ways to make a team of 2M,4W = 8C2 * 5C4 =28*5 =140 Possible ways to make a team of 3M,3W = 8C3* 5C3 = 56*10 = 560 Total possible ways = 140+560 = 700 Ans D it is.
_________________
Lets Kudos!!! 
Black Friday Debrief
Most important component: Cast you vote
|
|
|
|
|
|
Manager
Joined: 24 Mar 2010
Posts: 82
Followers: 0
Kudos [?]:
8
[0], given: 133
|
Re: Cooking Team Combinations [#permalink]
24 Dec 2012, 02:32
Could someone point out where my thought process is faltering. I did 8C2 * 5C3 * 8C18C1 - after choosing 2 men and and 3 women it doesn't matter who you pick from the remaining 8, so 8C1Await valued response.
_________________
- Stay Hungry, stay Foolish -
|
|
|
|
|
|
GMAT Club team member
Joined: 02 Sep 2009
Posts: 12104
Followers: 1879
Kudos [?]:
10115
[0], given: 961
|
Re: Cooking Team Combinations [#permalink]
24 Dec 2012, 02:49
eaakbari wrote: Could someone point out where my thought process is faltering.
I did
8C2 * 5C3 * 8C1
8C1 - after choosing 2 men and and 3 women it doesn't matter who you pick from the remaining 8, so 8C1
Await valued response. This way you are counting some teams more than once. Consider that you get A and B (men) from 8C2, X, Y, Z (women) from 5C3 and C (man) from 8C1, so your group is {A, B, C, X, Y, Z}. But if you get A and C (men) from 8C2, X, Y, Z (women) from 5C3 and B (man) from 8C1, your group will still be {A, B, C, X, Y, Z}. Hope it's clear.
_________________
PLEASE READ AND FOLLOW: 11 Rules for Posting!!!
RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders
COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. NEW!!! ,11 Mixed Questions NEW!!!, 12 Fresh Meat NEW!!!
DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set. NEW!!!, 11 New DS set. NEW!!!
What are GMAT Club Tests?
25 extra-hard Quant Tests
Find out what's new at GMAT Club - latest features and updates
|
|
|
|
|
|
Manager
Joined: 24 Mar 2010
Posts: 82
Followers: 0
Kudos [?]:
8
[0], given: 133
|
Re: Cooking Team Combinations [#permalink]
24 Dec 2012, 03:02
Bunuel wrote: eaakbari wrote: Could someone point out where my thought process is faltering.
I did
8C2 * 5C3 * 8C1
8C1 - after choosing 2 men and and 3 women it doesn't matter who you pick from the remaining 8, so 8C1
Await valued response. This way you are counting some teams more than once. Consider that you get A and B (men) from 8C2, X, Y, Z (women) from 5C3 and C (man) from 8C1, so your group is {A, B, C, X, Y, Z}. But if you get A and C (men) from 8C2, X, Y, Z (women) from 5C3 and B (man) from 8C1, your group will still be {A, B, C, X, Y, Z}. Hope it's clear. Ahhh, yes. I do understand now. Thanks, Bunuel, for the wonderful explanation.
_________________
- Stay Hungry, stay Foolish -
|
|
|
|
|
|
Director
Joined: 27 Aug 2012
Posts: 542
Followers: 23
Kudos [?]:
155
[0], given: 50
|
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
25 Dec 2012, 21:08
|
|
|
|
|
|
GMAT Club team member
Joined: 02 Sep 2009
Posts: 12104
Followers: 1879
Kudos [?]:
10115
[0], given: 961
|
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
26 Dec 2012, 03:26
|
|
|
|
|
|
Director
Joined: 27 Aug 2012
Posts: 542
Followers: 23
Kudos [?]:
155
[0], given: 50
|
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
26 Dec 2012, 05:22
Bunuel wrote: debayan222 wrote: OA: D-700. GMATPill/Bunuel, Is it really a 700+ level Q ? It's pretty easy guys...! In that case combinations going to be an easy topic in GMAT..  GMAT combination/probability questions are fairly straightforward, so you won't see much harder questions on these topics on the exam. Great to know that Bunuel...! Well, in that case Qs. in your signature and those in the GMAT Club tests (obviously apart from OG Qs.) would be suffice for 700+ in GMAT I think as far as combination/probability questions are concerned...! Appreciate your thoughts on this...
_________________
Press Kudos if I'm able to help you 
e-GMAT SC Resources-Consolidated :http://gmatclub.com/forum/e-gmat-s-all-sc-topics-consolidated-144985.html
ALL RC Resources-Consolidated :http://gmatclub.com/forum/all-rc-strategy-docs-by-experts-legendary-club-members-145027.html
ALL SC Resources-Consolidated :http://gmatclub.com/forum/all-sc-rules-official-qs-by-experts-legendary-club-members-145563.html
UPDATED : AWA compilations-109 Analysis of Argument Essays
Veritas Blog
|
|
|
|
|
|
Senior Manager
Joined: 13 Aug 2012
Posts: 468
Followers: 13
Kudos [?]:
88
[0], given: 11
|
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team [#permalink]
27 Dec 2012, 22:56
gmatpill wrote: A team of 6 cooks is chosen from 8 men and 5 women. The team must have at least 2 men and at least 3 women. How many ways can this team be created?
A) 140
B) 320
C) 560
D) 700
E) 840
M M W W W M/W This means we could have either combinations: (1) 2MEN 4WOMEN (2) 3MEN 3WOMEN We will add the total number of both possibilities: 8!/6!2! * 5!/4!1! + 8!/3!5! * 5!/3!2! = 140 + 560 = 700 Answer: D
|
|
|
|
|
|
|
Re: A team of 6 cooks is chosen from 8 men and 5 women. The team
[#permalink]
27 Dec 2012, 22:56
|
|
|
|
|
|
|
|
|
|
|
close
