Got E.

Let X be the first piece.

Second piece-----> 40-X.

Now, X is used to form a circle

=> X = 2*(pie)*r ,.....................Eqn(1) ,(

Circumference = length of wire)

Area of Circle---------> (pie)*r^2.

Also,let side of square be a,

40 - X = 4*a , ........................(Perimeter (4*a) = Length (40 -X) )

Substituting X from Eqn(1) ,

=> 40 - {2*(pie)*r} = 4*a ,

=> 10 - { ((pie)*r) / 2 } = a.

Area of Square = a^2

Hence total area ==> (pie)r^2 +(10-1/2 (pie)r)^ 2

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