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A thinly stretched pharmaceuticals company operates three

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A thinly stretched pharmaceuticals company operates three [#permalink] New post 16 Oct 2005, 17:52
00:00
A
B
C
D
E

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A thinly stretched pharmaceuticals company operates three business divisions: drugs, biotech, and medical devices. Each division employs 50 people each. There is a special task force of 10 employees who belong to all three divisions. In addition, there are “cross specialist positionsâ€

Last edited by Titleist on 17 Oct 2005, 12:55, edited 7 times in total.
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 [#permalink] New post 16 Oct 2005, 18:34
50 in each division.

50 total cross specialists
20 for B and M
18 for D and M
12 for B and D

10 for all B M and D.

It gives us
8 only for B
2 only for M
10 only for D.

If I pick all those with M and D it comes to be 72. Giving me probability of 72/80.
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 [#permalink] New post 17 Oct 2005, 01:50
to admit am bad in probability but, this is what i will do...

10 (drugs) + 2 (Medical) + 10(all 3)
=22/150
=11/75

whats the OA
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 [#permalink] New post 17 Oct 2005, 11:09
sushom101 wrote:
to admit am bad in probability but, this is what i will do...

10 (drugs) + 2 (Medical) + 10(all 3)
=22/150
=11/75

whats the OA


probability of picking either a drug or med dev specialist - so you must exclude cross specialists and task force members

total employees = 80

thus picking a drug employee 10/80

picking a med dev. employee 2/80

add since it's 'or' 10/80 + 2/80 =3/20

Last edited by Titleist on 17 Oct 2005, 12:56, edited 2 times in total.
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 [#permalink] New post 17 Oct 2005, 12:53
I am getting medical dev probability as 2 / 80.

Hence the total as 10/80 + 2/80 = 12/80 = 3/20.

Should the question read as Drug or Biotech divison?
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 [#permalink] New post 17 Oct 2005, 12:57
sudhagar wrote:
I am getting medical dev probability as 2 / 80.

Hence the total as 10/80 + 2/80 = 12/80 = 3/20.

Should the question read as Drug or Biotech divison?


good catch - just made the changes. OA is 3/20
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 [#permalink] New post 17 Oct 2005, 15:31
Titleist wrote:

probability of picking either a drug or med dev specialist - so you must exclude cross specialists and task force members

total employees = 80

thus picking a drug employee 10/80

picking a med dev. employee 2/80

add since it's 'or' 10/80 + 2/80 =3/20


Can you please explain how did you get total number of employees to be 80?

I am coming up with :
50 + 50 + 50 - (50) + 10 or 110

Question:
what is the probability that if an employee is chosen at random from this company that he or she is an employee of either the drug division or the medical devices division but not both?

Also, as question does not explicitly removes from scope, why didnt you pick employees that are:
cross specialist with BOTH Drug & Biotech OR
cross specialist with BOTH Med dev & Biotech
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 [#permalink] New post 17 Oct 2005, 15:43
duttsit wrote:
Titleist wrote:

probability of picking either a drug or med dev specialist - so you must exclude cross specialists and task force members

total employees = 80

thus picking a drug employee 10/80

picking a med dev. employee 2/80

add since it's 'or' 10/80 + 2/80 =3/20


Can you please explain how did you get total number of employees to be 80?

I am coming up with :
50 + 50 + 50 - (50) + 10 or 110

Question:
what is the probability that if an employee is chosen at random from this company that he or she is an employee of either the drug division or the medical devices division but not both?

Also, as question does not explicitly removes from scope, why didnt you pick employees that are:
cross specialist with BOTH Drug & Biotech OR
cross specialist with BOTH Med dev & Biotech



Look at jainvineet's explanation - it's correct as so far as how he calculated the number of individuals.
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 [#permalink] New post 17 Oct 2005, 15:53
Titleist wrote:

Look at jainvineet's explanation - it's correct as so far as how he calculated the number of individuals.


I understood the indivisual numbers in jainvineet's explanation. But my question remains how did total comes out to be : 80
Also how do we interpret question so as not to include cross specilist with Bio.
Am sure I am missing some rudimentary point. Thanks.
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 [#permalink] New post 17 Oct 2005, 16:13
duttsit wrote:
Titleist wrote:

Look at jainvineet's explanation - it's correct as so far as how he calculated the number of individuals.


I understood the indivisual numbers in jainvineet's explanation. But my question remains how did total comes out to be : 80
Also how do we interpret question so as not to include cross specilist with Bio. Am sure I am missing some rudimentary point. Thanks.


We interpret the question as simply what is the probability that the individual we pick at random is an employee of ONLY Drugs or ONLY Medical Devices - and not both - so that would mean you exclude cross specialists within drugs/med devices.


I really hope this helps!

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Handy venn! I got 3/20 too.. [#permalink] New post 17 Oct 2005, 17:08
I found a Venn Diagram quite useful for these kinda Q's. Attached is an image (JPEG) of the Venn for this Q.

So from the venn diag..
Probability of desired event = (10+2)/80 = 12/80 = 3/20

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Re: Handy venn! I got 3/20 too.. [#permalink] New post 17 Oct 2005, 17:13
mbaqst wrote:
I found a Venn Diagram quite useful for these kinda Q's. Attached is an image (JPEG) of the Venn for this Q.

So from the venn diag..
Probability of desired event = (10+2)/80 = 12/80 = 3/20


WOW :shock:
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 [#permalink] New post 17 Oct 2005, 18:20
why are the employees who are both Drug and Biotech ,
both Medical Device and Biotech excluded ?

The question was only asking for the exclusion for those that are both
in Drug and Medical Device, right ?
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 [#permalink] New post 17 Oct 2005, 19:21
qpoo wrote:
why are the employees who are both Drug and Biotech ,
both Medical Device and Biotech excluded ?

The question was only asking for the exclusion for those that are both
in Drug and Medical Device, right ?



THe question is asking for the probability of picking someone who works for either (not both) drug OR medical devices division. Not both. That is why you must exclude the cross specialists.



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 [#permalink] New post 06 Nov 2005, 15:28
Why do you exclude B|M (that is 20) and B|D (that is 12)

((22 + 2) + (10 + 12))/80

11/20

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Re: PS Word Problem - Overlapping Set/Probability Combo [#permalink] New post 06 Nov 2005, 19:50
[quote="Titleist"]A thinly stretched pharmaceuticals company operates three business divisions: drugs, biotech, and medical devices. Each division employs 50 people each. There is a special task force of 10 employees who belong to all three divisions. In addition, there are “cross specialist positionsâ€
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Re: PS Word Problem - Overlapping Set/Probability Combo [#permalink] New post 07 Nov 2005, 04:07
A good question for venn diagram.

D - Drug
B - biotech
M - Medical

n(DnBnM) = 10
n(DnB) = 12
n(DnM) = 18
n(BnM) = 20
n(d) = 10 (i.e. 50 - (12+10+18))
n(B) = 8 (i.e. 50 - (12 + 10 + 20))
n(M) = 2 (i.e. 50 - (18 + 10 + 20))

Total emp = n(d) + n(B) + n(M) + n(dnb) + n(DnM) + n(BnM) + n(DnBnM)
= 10 + 8 + 2 + 12 + 18 + 20 + 10 = 80

We need to find the probablity of an employee of either the drug division or the medical devices division but not both. i.e. We only need to count
n(d) + n(M) = 12/80 = 3/20
Re: PS Word Problem - Overlapping Set/Probability Combo   [#permalink] 07 Nov 2005, 04:07
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