A total of n trucks and cars are parked in a lot. If the num

D.
x+x/4=n => x=4n/5 => 2x/3=8n/15

Let there be c cars and t trucks and p pickup trucks
n = t+c
t=4c
So n = 5c
(2/3)t = p
p = (2/3)t = (2/3)(4c) = (8/3)c = (8/3)(n/5) = (8/15)n

Answer is (d)

Lets consider the number of trucks = x
Hence, total number of cars is = x/4
from the question we know, x+x/4 = n = > x = 4n/5
Number of trucks that are pickups = (2/3)4n/5 = 8n/15.
D is the answer.

Cheers!

Lets say Total truck is 12. So car is 3.
Now pickups are =2/3rd of 12= 8
so total fraction is 8/15 ..ans

C = Cars, T = Trucks, and P = Pickups.

\(C + T = n\)

\(C = \frac{1}{4} T\)
\(\frac{2}{3}T = P\)

We'd like to write everything in terms of Pickups, since that's what the question is asking us about. Thus,

\(T = \frac{3}{2}P\),
\(C = \frac{1}{4}T = \frac{1}{4} * \frac{3}{2} P = \frac{3}{8}P\)

Therefore,

\(n = C + T = \frac{3}{8} P + \frac{3}{2} P = \frac{30}{16}P = \frac{15}{8}P.\)

Solving for P, we see that \(P = \frac{8}{15} n.\)

Answer: D

This is all variables in answer choices question. So lets pick smart numbers. Let n=15 {why 15? Since cars=1/4*trucks, total trucks+cars should be divisible by 5 (1+4). Additionally since we have another fraction 2/3 to work with, the total should be divisible by 3}
n=15
cars+trucks= 15
cars+4*cars = 15 -> cars=3 so trucks=12
pick-up trucks = 12*2/3 = 8
Now plug 15 in answer choices. Only D gives 8. Ans D

let t=number of trucks
n=t+(t/4)=5t/4
let p=number of pickups
t=3p/2
substituting, n=5(3p/2)/4
p=8/15 n

Number of trucks = x
Number of cars = 1/4x

Therefore, x +1/4x = n ( Total number of vehicles parked)
X= 4n/5

We are given 2/3 of x are pick up trucks.
So 2/3 *4n/5 = 8/15n

t+c = n
c = t/4

t+t/4 = n
t = 4/5 n

c = 2/3 t = 2/3 * 4/5 = 8/15 n

Answer D

We can let the number of cars = c and number of trucks = t; thus:

c + t = n

and

c = (1/4)t

Thus:

(1/4)t + t = n

t + 4t = 4n

5t = 4n

t = 4n/5

Since 2/3 of the trucks are pickups, there are (2/3)(4n/5) = 8n/15 pickups in the parking lot.

Answer: D

Total: 'n = trucks(t) + cars(c)'

Number of cars is 1/4 the number of trucks: c = \(\frac{1}{4}\) * t

=> n = \(\frac{1}{4}\) * t + t = \(\frac{5}{4}\) * t OR t = \(\frac{4}{5}\) * n

\(\frac{2}{3}\) of the trucks are pickups. Therefore,

=> t = \(\frac{4}{5}\) * n

=> \(\frac{2}{3}\) * t = \(\frac{2}{3}\) * \(\frac{4}{5}\) * n

=> Parked trucks: \(\frac{8 }{ 15}\) * n

Answer D

Given: A total of n trucks and cars are parked in a lot.
Asked: If the number of cars is 1/4 the number of trucks, and 2/3 of the trucks are pickups, how many pickups, in terms of n, are parked in the lot?

Let the number of pickup trucks parked in the lot = x

Number of trucks = 3x/2
Number of cars = 3x/8

3x/2 + 3x/8 = n
15x/8 = n
x = 8n/15

IMO D

what the difference between 1/4 the number vs 1/4 of the number ? any other similar twists when it comes to interpreting fractions

hi chetan2u VeritasKarishma

Hi

Both mean the same mathematically, that is 1/4*number

Let's assume the number of trucks is represented by "t" and the number of cars is represented by "c."

According to the given information, the number of cars is 1/4 the number of trucks:

c = (1/4) * t

Next, it states that 2/3 of the trucks are pickups:

Pickup trucks = (2/3) * t

Now, we need to express the number of pickups in terms of "n," which represents the total number of trucks and cars in the lot.

Total number of vehicles = t + c

Since c = (1/4) * t, we can substitute this into the equation:

Total number of vehicles = t + (1/4) * t

Total number of vehicles = (5/4) * t

Since n represents the total number of vehicles, we can set up the equation:

n = (5/4) * t

Now, let's express the number of pickups in terms of "n":

Pickup trucks = (2/3) * t

Substituting the value of t from the equation n = (5/4) * t:

Pickup trucks = (2/3) * [(4/5) * n]

Simplifying the expression:

Pickup trucks = (8/15) * n

Therefore, the number of pickups, in terms of n, parked in the lot is (8/15) n.

The correct answer is (D) 8/15 n.