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A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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21 Feb 2011, 07:06

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69% (02:31) correct
31% (01:02) wrong based on 121 sessions

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A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T. (2) The number of female residents who were not born in Town T is twice the number of female residents who were born in Town T.

Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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21 Feb 2011, 07:20

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A Town T has 20,000 residents, 60 percent of whom are female. What percent of the residents were born in Town T?

This question can be best described using a table. I don't know how would I draw that. Someone please suggest.

Female=12000 Male=8000

Female born in T=x Female not born in T=12000-x

Male born in T=y Male not born in T= 8000-y

(1) The number of female residents who were born in Town T is twice the number of male residents who were not born in Town T. x=2*y Not sufficient.

(2) The number of female residents who were not born n Town T is twice the number of female residents who were born in Town T. 12000-x=2x 3x = 12000 x=4000 We know the number of female born in T; 4000; Number of females not born; 8000 Know nothing about the male born in T i.e. y.

Combining both; x=2y 4000 = 2y y=2000

Total people born in T=2000+4000=6000 or (6/20)*100=30% Sufficient.

Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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16 Aug 2011, 08:00

the question seems to be incorrect.. in the final equation, i get total male as 6000 whereas the question gives 8000.. experts, any comments?? _________________

Appreciation in KUDOS please! Knewton Free Test 10/03 - 710 (49/37) Princeton Free Test 10/08 - 610 (44/31) Kaplan Test 1- 10/10 - 630 Veritas Prep- 10/11 - 630 (42/37) MGMAT 1 - 10/12 - 680 (45/34)

Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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18 Aug 2011, 11:29

let's make a table and write all values from stem, statement 1 & 2

From Stem, total females = 60% of 20,000 = 12,000 From statement 1, if male(M) not born (NB) in town T are x, then female(F) born(B) in town = 2x From statement 2, F(NB) = 2 F(B) Combining both the statements, we have following table

| M | F | -------|-------|------- |--------- B | | 2x | -------|-------|------- |-------- NB | x | 2(2x) | -------|-------|--------|------------ | | 12000 |

So, 2x + 2(2x) = 12,000.

Rest is all arithmetic, we can calculate each cell, hence final answer. Remember no need to go fro exact answer. We now know, both statements are sufficient. Answer is C.

Re: A Town T has 20,000 residents, 60 percent of whom are female. What per [#permalink]

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06 Jun 2015, 19:53

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