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A train always travels at one of two speeds: 160 km/hr in [#permalink]
08 Oct 2007, 10:55
00:00
A
B
C
D
E
Difficulty:
(N/A)
Question Stats:
0% (00:00) correct
0% (00:00) wrong based on 0 sessions
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A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas.
(2) The distance from A to B is more than 1000 km.
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
Say Distance is 120km.
Rural || Urban
R 160 || 40
T 1/2hr || 1hr
D 80 || 40
Rural distance is 80 b/c 2/3*120=80. (same reasoning for Urban)
So we have 120/(1/2hr+1hr) --> 120/3/2Hrs ---> 120*2/3 ->80kph
So NO the train did not exceed an average speed of 100kmph
Just looking at B it says the distance exceeds 1000km. If you don't feel comfortable w/ the above. Just try 1200km. You will see the answer is still 80kmph
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
Hi Kevin,
Have you recently join Manhattan Review?
Congrats/goodluck..
kevincan wrote:
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
Logic of the question suggests that we need only know what fraction of the entire trip was rural vs not, in order to find the actual time.
1st premise provides us exactly this information.
2nd premise is a dud.
By the way, this is a great candidate for time saving by avoiding unnecessary math. If you can visualize this problem, you need not write any math down to solve it -- give yourself more time for the other calc intensive problems down the road.
Another GMAC favorite in this genre is "did the train ever exceed speed X during such and such trip?". Well, maybe for a split second the train gassed it up and went super duper fast, while noone was looking... the answer to this question is usually E, because you usually cannot know if there was a split second surge in speed while the rest of the trip was normal.
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
from basics, what i know is that in order to find the average speed we need to find the distance and time only.
we do not have the time it took the train to travel with different rates of speed so. we can find the time using both of the statements.
i think it is C. speed is >40 mp/hour
will post the explanation if it is the correct answer.
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.
What is average speed? It is the total distance travelled divided by the total time. If we imagine that a car traveled half the distance with the speed 50 mph, and the other half with the speed 100 mph, how to get the average speed?
Let's put 40 miles as the total distance. Hence, 20 miles is 1/2 of it.
The first half was covered in 0.4 of an hour (i.e. in 24 min.) The second one - 0.2 of an hour (12 min.). Therefore, the total time equals 0.6 of an hour, and the total distance is 40 miles.
As a result, the average speed is 40 miles/0.6 of an hour, the average speed is about 66.6(6) mph.
Now let's look at the problem. If we know that more than 2/3 of the distance is made with the speed 160, let's just put some numbers.
Distance = 300. 200 with 160mph, 100 - 40 mph. The average speed is MORE than 80 mph (it would be 80 if EXACTLY 2/3 of the route is covered with superspeed ) We don't know, how much is the exact number. It can be greater then 100, if, for example, the train travel 295 "rural" miles and 5 urban (average speed equals 155 mph). 295 out of 300 miles is still "more than 2/3 of the distance".
As a result, A is useless. IF exactly 2/3 of the distance mean more than 100 mph, anyway, then we would use it. However, it does not.
Finally, B is useless, since the average speed is not bound to the total distance directly, but through the time spent.
My answer is E.
Please, fell free to correct any of my grammar mistakes. I am Russian, and for the moment I am fiercely trying to remember anything about English and its grammar.
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas (2) The distance from A to B is more than 1000 km
I guess i got it. Suppose the distance is 1200km.
rural area = 80% of 1200km = 960km
no of hours = 6 hours
urban area = 20% of 1200km = 240km
no of hours = 6 hours
so the average speed = (960+240)/12 = 100 km/h
Suppose: the rural area = 90% of 1200km = 1080 km
no of hours = 1080/160 hours
urban area = 10% of 1200 km = 120 km
no of hours = 3 hours
so the average speed = (1080 + 120)/(1080/160 + 12) => 100 km/h
A train always travels at one of two speeds: 160 km/hr in rural areas and 40 km/hr in urban areas. Was its average speed from A to B greater than 100 km/hr?
(1) More than 2/3 of the distance from A to B is through rural areas. (2) The distance from A to B is more than 1000 km.