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A train met with an accident 60km away from station A. It co

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A train met with an accident 60km away from station A. It co [#permalink] New post 18 Oct 2011, 06:37
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A
B
C
D
E

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70% (03:47) correct 29% (04:04) wrong based on 41 sessions
A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

A. 60 km/hr
B. 55 km/hr
C. 65 km/hr
D. 70 km/hr
E. 48 km/hr
[Reveal] Spoiler: OA

Last edited by Bunuel on 12 Jul 2013, 13:09, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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Re: train speed [#permalink] New post 18 Oct 2011, 07:04
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dreambeliever wrote:
A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

a. 60 km/hr
b. 55 km/hr
c. 65 km/hr
d. 70 km/hr
e. 48 km/hr



let the original speed be 6x. A/q, traveling 60 km at 5/6th of original speed costs him 12 minutes etc

60/5x =60/6x +12/60 -> x =10 , 6x= 60.

Ans A
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Re: train speed [#permalink] New post 18 Oct 2011, 08:10
My solution:
s=original spped, t=time taken in minutes to cover journey usually
(t+72-60/s)(5/6s)+60=(t+60-120/s)(5/6s)+120...........as total distance covered is same in both cases
solving, s=1 km/min=60km/hr
hence ans A
I know its too long.....but taking shortcuts was messing me up....
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Re: train speed [#permalink] New post 18 Oct 2011, 11:15
Expert's post
dreambeliever wrote:
A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

a. 60 km/hr
b. 55 km/hr
c. 65 km/hr
d. 70 km/hr
e. 48 km/hr


The logical approach here is this:

The accident took place 60 km from A. The train was delayed by 1hr 12 min. If it had instead taken place 120 km from A, it would have been only 1 hr late. What does this 12 min gap in time signify? It is the delay caused by reducing the speed by (1/6)th over a distance of 60 km. The ratio of the speed over this 60 km stretch is 5:6 (speed reduced by a sixth : original speed)
Time taken 6:5 (Time taken with reduced speed : original time taken)
We know this difference of 1 in time taken is given by 12 min. So original time taken is 12*5 = 60 min = 1 hr
Time taken is 1 hr to cover a distance of 60 km so speed = 60 km/hr
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Re: train speed [#permalink] New post 18 Oct 2011, 19:20
Agree with A but took too long to reach the solution:(
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Re: train speed [#permalink] New post 22 Oct 2011, 07:26
Let the original speed be v .

In case 2, the 60 kms further which the train traveled was with speed v.
In case 1, these 60 kms (which in case 2 the train traveled further where accident happened) was traveled at a speed of (5v)/6. And this caused the extra 12 mins delay in case 1.

So,

60/v +12/60=60/((5v)/6)
v=60
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Re: train speed [#permalink] New post 24 Oct 2011, 08:18
my sol. was just too lengthy..

let s be the original speed and x+60 be total distance between A and B:
60/s + x/(5s/6) = (x+60)/s + 72/60

Also, 120/s + (x-60)/(5s/6) = (x+60)/s + 1

subtracting the 2 equations: 60/s + 60/(5s/6) = 12/60
therefore s = 60.

thanks Everybody!!
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Re: A train met with an accident 60km away from station A. It co [#permalink] New post 14 Feb 2014, 01:36
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Re: A train met with an accident 60km away from station A. It co   [#permalink] 14 Feb 2014, 01:36
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