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# A train met with an accident 60km away from station A. It co

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Manager
Joined: 24 Nov 2010
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Location: United States (CA)
Concentration: Technology, Entrepreneurship
Schools: Ross '15, Duke '15
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A train met with an accident 60km away from station A. It co [#permalink]  18 Oct 2011, 06:37
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64% (04:08) correct 36% (06:42) wrong based on 97 sessions
A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

A. 60 km/hr
B. 55 km/hr
C. 65 km/hr
D. 70 km/hr
E. 48 km/hr
[Reveal] Spoiler: OA

Last edited by Bunuel on 12 Jul 2013, 13:09, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
Manager
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Re: train speed [#permalink]  18 Oct 2011, 07:04
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dreambeliever wrote:
A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

a. 60 km/hr
b. 55 km/hr
c. 65 km/hr
d. 70 km/hr
e. 48 km/hr

let the original speed be 6x. A/q, traveling 60 km at 5/6th of original speed costs him 12 minutes etc

60/5x =60/6x +12/60 -> x =10 , 6x= 60.

Ans A
Manager
Joined: 16 Sep 2011
Posts: 182
Concentration: Strategy, Operations
Schools: ISB '15
GMAT 1: 720 Q48 V40
GPA: 3.18
WE: Supply Chain Management (Manufacturing)
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Kudos [?]: 45 [0], given: 34

Re: train speed [#permalink]  18 Oct 2011, 08:10
My solution:
s=original spped, t=time taken in minutes to cover journey usually
(t+72-60/s)(5/6s)+60=(t+60-120/s)(5/6s)+120...........as total distance covered is same in both cases
solving, s=1 km/min=60km/hr
hence ans A
I know its too long.....but taking shortcuts was messing me up....
Veritas Prep GMAT Instructor
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Re: train speed [#permalink]  18 Oct 2011, 11:15
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Expert's post
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dreambeliever wrote:
A train met with an accident 60km away from station A. It completed the remaining journey at 5/6th of the original speed and reached station B 1hr 12mins late. Had the accident taken place 60km further, it would have been only 1hr late. what was the original speed of the train?

a. 60 km/hr
b. 55 km/hr
c. 65 km/hr
d. 70 km/hr
e. 48 km/hr

The logical approach here is this:

The accident took place 60 km from A. The train was delayed by 1hr 12 min. If it had instead taken place 120 km from A, it would have been only 1 hr late. What does this 12 min gap in time signify? It is the delay caused by reducing the speed by (1/6)th over a distance of 60 km. The ratio of the speed over this 60 km stretch is 5:6 (speed reduced by a sixth : original speed)
Time taken 6:5 (Time taken with reduced speed : original time taken)
We know this difference of 1 in time taken is given by 12 min. So original time taken is 12*5 = 60 min = 1 hr
Time taken is 1 hr to cover a distance of 60 km so speed = 60 km/hr
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Current Student Joined: 18 Jun 2010 Posts: 149 Followers: 0 Kudos [?]: 22 [1] , given: 2 Re: train speed [#permalink] 18 Oct 2011, 19:20 1 This post received KUDOS Agree with A but took too long to reach the solution:( Intern Joined: 03 Oct 2011 Posts: 25 Followers: 0 Kudos [?]: 6 [0], given: 7 Re: train speed [#permalink] 22 Oct 2011, 07:26 Let the original speed be v . In case 2, the 60 kms further which the train traveled was with speed v. In case 1, these 60 kms (which in case 2 the train traveled further where accident happened) was traveled at a speed of (5v)/6. And this caused the extra 12 mins delay in case 1. So, 60/v +12/60=60/((5v)/6) v=60 Manager Joined: 24 Nov 2010 Posts: 209 Location: United States (CA) Concentration: Technology, Entrepreneurship Schools: Ross '15, Duke '15 Followers: 2 Kudos [?]: 50 [0], given: 7 Re: train speed [#permalink] 24 Oct 2011, 08:18 my sol. was just too lengthy.. let s be the original speed and x+60 be total distance between A and B: 60/s + x/(5s/6) = (x+60)/s + 72/60 Also, 120/s + (x-60)/(5s/6) = (x+60)/s + 1 subtracting the 2 equations: 60/s + 60/(5s/6) = 12/60 therefore s = 60. thanks Everybody!! GMAT Club Legend Joined: 09 Sep 2013 Posts: 6106 Followers: 340 Kudos [?]: 68 [0], given: 0 Re: A train met with an accident 60km away from station A. It co [#permalink] 14 Feb 2014, 01:36 Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________ Manager Joined: 03 Jan 2015 Posts: 68 Concentration: Strategy, Marketing WE: Research (Pharmaceuticals and Biotech) Followers: 0 Kudos [?]: 11 [0], given: 224 Re: A train met with an accident 60km away from station A. It co [#permalink] 28 Jan 2015, 19:03 Hi all, Can someone please help me think through this problem? Given: It arrives 1 hr 12 min late if the accident took 60 km further from A It arrives 1 hr late if the accident took 120 km further from A It implies: the two "accident spots" are separated by 12 min and 60 km Hence: R = (60)*(60/12) = 300 kmph Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 5853 Location: Pune, India Followers: 1479 Kudos [?]: 7944 [1] , given: 190 Re: A train met with an accident 60km away from station A. It co [#permalink] 28 Jan 2015, 22:51 1 This post received KUDOS Expert's post thorinoakenshield wrote: Hi all, Can someone please help me think through this problem? Given: It arrives 1 hr 12 min late if the accident took 60 km further from A It arrives 1 hr late if the accident took 120 km further from A It implies: the two "accident spots" are separated by 12 min and 60 km Hence: R = (60)*(60/12) = 300 kmph You are assuming that the train covered 60 km in 12 mins. That gives you the speed as 300 kmph. But is that really the case? 12 mins is the difference in the time taken to cover 60 kms at two different speeds. It is the delay caused by reducing the speed by (1/6)th over a distance of 60 km. The ratio of the speed over this 60 km stretch is 5:6 (speed reduced by a sixth : original speed) Time taken 6:5 (Time taken with reduced speed : original time taken) We know this difference of 1 in time taken is given by 12 min. So original time taken is 12*5 = 60 min = 1 hr Time taken is 1 hr to cover a distance of 60 km so speed = 60 km/hr _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: A train met with an accident 60km away from station A. It co   [#permalink] 28 Jan 2015, 22:51
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