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A train travels 60mph on the first half of it trip from

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Joined: 22 Sep 2007
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A train travels 60mph on the first half of it trip from [#permalink]  14 Dec 2007, 09:00
A train travels 60mph on the first half of it trip from Carney to Jewisttville. The same train travels 75mph on the second half of the trip. Of the following, which is the closest average speed, in mph, for the whole trip?

a) 65mph

b) 66.7mph

c) 67.5mph

d) 68mph

e) 70mph
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That's correct, pls show (step by step) how u got it. Thanks.
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Formula for average speed is Total distance divided by total time. since we have not been given a distance, we can choose a distance that is evenly divided by the two speeds 75 and 60. i used 600 so the 1st half is 300 and 2nd half is also 300 totalling 600. when i divide both distances, i get 4 hours and 5 hour equalling to 9 hrs total. now we divide 600 by 9 to get the average speed of 66.7 Alsways remeber the formula rate * time= distance because you can always manipulate the formula.
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Re: Distance [#permalink]  14 Dec 2007, 10:18
inwosu wrote:
A train travels 60mph on the first half of it trip from Carney to Jewisttville. The same train travels 75mph on the second half of the trip. Of the following, which is the closest average speed, in mph, for the whole trip?

a) 65mph

b) 66.7mph

c) 67.5mph

d) 68mph

e) 70mph

first half: t=time, d= distance and 60 is the rate.

so 60t=d/2

second half: T=time d= (total distance) and 75 is the rate

75T=d/2

we want to know what

d/(t+T) =?

T=d/150
t=d/120

d/(d/150+d/120) --> 600/9 ~66.7
Re: Distance   [#permalink] 14 Dec 2007, 10:18
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