Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 26 Apr 2015, 22:32

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A varaint of a MGMAT problem. A , B, and C have 5 bagels

Author Message
TAGS:
CEO
Joined: 15 Aug 2003
Posts: 3469
Followers: 61

Kudos [?]: 701 [0], given: 781

A varaint of a MGMAT problem. A , B, and C have 5 bagels [#permalink]  15 Dec 2003, 07:09
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
A varaint of a MGMAT problem.

A , B, and C have 5 bagels to share. If any one of the them can be given any whole number of bagels from 0 to 5, in how many different ways can the bagels be distributed?

(A) 21
(B) 42
(C) 120
(D) 504
(E) 5040

Last edited by Praetorian on 15 Dec 2003, 08:06, edited 2 times in total.
 Manhattan GMAT Discount Codes Kaplan GMAT Prep Discount Codes Veritas Prep GMAT Discount Codes
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 10 [0], given: 0

5 0 0 x3
4 1 0 x6
3 1 1 x3
3 2 0 x6
2 2 1 x3

21, I think...
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 10 [0], given: 0

It would be great to know the way to use theory to do this problem...
CEO
Joined: 15 Aug 2003
Posts: 3469
Followers: 61

Kudos [?]: 701 [0], given: 781

stoolfi wrote:
5 0 0 x3
4 1 0 x6
3 1 1 x3
3 2 0 x6
2 2 1 x3

21, I think...

That is correct. Great job.

thanks
praetorian
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 10 [0], given: 0

21, of course, is the sum of numbers from 1-6.

Which makes sense.

If person A has 0 bagels, person B can have 0,1,2,3,4,5 and person C will get whatever is left.
If person A has 1 bagels, person B can have 0,1,2,3,4 and person C will get whatever is left.
If person A has 2 bagels, person B can have 0,1,2,3 and person C will get whatever is left.
If person A has 3 bagels, person B can have 0,1,2 and person C will get whatever is left.
If person A has 4 bagels, person B can have 0,1 and person C will get whatever is left.
If person A has 5 bagels, person B can have 0 and person C will get whatever is left.

But there's still gotta be a better way...
Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 10 [0], given: 0

When you say that this problem is reminiscent of an old MGMAT problem, are you referring to this thread?

http://www.gmatclub.com/phpbb/viewtopic ... ght=#17866

Because we detemined the formula for positive integers, but the addition of ZERO is the difference between that problem and this one, and I cannot figure out how to compensate/adjust for that.
CEO
Joined: 15 Aug 2003
Posts: 3469
Followers: 61

Kudos [?]: 701 [0], given: 781

stoolfi wrote:
When you say that this problem is reminiscent of an old MGMAT problem, are you referring to this thread?

http://www.gmatclub.com/phpbb/viewtopic ... ght=#17866

Because we detemined the formula for positive integers, but the addition of ZERO is the difference between that problem and this one, and I cannot figure out how to compensate/adjust for that.

no stoolfi, this problem is from MGMAT's archives.

let me see if i can send you the explanation.

great work

keep posting

thanks
praetorian
Director
Joined: 14 Oct 2003
Posts: 588
Location: On Vacation at My Crawford, Texas Ranch
Followers: 1

Kudos [?]: 9 [0], given: 0

Here is another approach (virtually the same as Stoolfi's approach)

With:

5 Bagels (means 0 bagels for everyone else): 3C1=3
4 Bagels (4,1,0) = 3C1*2C1=6
3 Bagels (3,2,0) = 3C1*2C1=6
3 Bagesl (3,1,1) = 3C1=3
2 Bagels (2,2,1) = 3C1=3

Sum=21
Similar topics Replies Last post
Similar
Topics:
1 MGMAT Word Problem Book 4 or 5 for probability? 2 02 May 2014, 19:37
If 5a = 9b = 15c, what is the value of a + b + c? 0 21 Aug 2013, 20:12
If each of a, b and c is positive, and a = 5b + 7c, what is 1 26 Nov 2010, 09:57
If (c-a)/(c-b) = 2, then (5b-5a)/(c-a) = A. 0.5 B. 1 C. 1.5 4 21 Aug 2007, 08:55
This is MGMAT's challenge problem of the week. Have fun ! 9 09 Jan 2006, 00:48
Display posts from previous: Sort by