A vegetable seller has 50%kgs of vegetable, part of which

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A vegetable seller has 50%kgs of vegetable, part of which [#permalink]

21 Dec 2003, 12:43

A vegetable seller has 50%kgs of vegetable, part of which she sells at 10% profit and rest of them sells at 6% profit. On the whole she made a total profit of 9% .What was the amount she sold at 10% ?
a)12.5kgs
b)6.25kgs
c)37.5kgs
d)18.75kgs
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shubhangi

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21 Dec 2003, 13:31

37.5kgs out of 50 kgs not 50%kgs (just a correction)

1.1*X + 1.06(50-X) = 1.09 * 50
solve for X

Intern

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21 Dec 2003, 14:48

An easier way to express the equation is

x* 10/100 + (50 -x)*6/100 = 50*9/100

or 10x + 300 - 6x = 450

Ans - C

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22 Dec 2003, 21:44

I used aproach similar to aproach which we are using for solution problem ( when you have to mix different %)

9 (%) = ( X*6 + Y*10) / (X+Y)......(1)

X+Y = 50.....................................(2)

3X=Y....(1)

(1) and (2) => y=37,5

So, the answer is C.

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23 Dec 2003, 07:40

This one can be solved with absolutely no calculation. If she sold two tranches - one at 10% profit and the other at 6% profit (with the weighted after being 9% profit) then she must have sold more than half at 10% profit.

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23 Dec 2003, 07:49

Titleist wrote:

yes, your logic will work in this particular case, but we need to calculate if the answer choices are close.

good work..!

Director

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23 Dec 2003, 08:30

dj wrote:

Titleist wrote:

yes, your logic will work in this particular case, but we need to calculate if the answer choices are close.

good work..!

Thanks Dj, I agree - this problem is a mid 500 level question - if it were a mid 600 then the answer choices would be closer and I would have to get off my lazy fanny and actually do some calculations! :lol:

[#permalink] 23 Dec 2003, 08:30

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A vegetable seller has 50%kgs of vegetable, part of which

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A vegetable seller has 50%kgs of vegetable, part of which

A vegetable seller has 50%kgs of vegetable, part of which

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