A very very difficult math : GMAT Problem Solving (PS)
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A very very difficult math

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Intern
Joined: 21 Aug 2011
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A very very difficult math [#permalink]

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24 Aug 2011, 01:02
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(N/A)

Question Stats:

25% (00:00) correct 75% (00:50) wrong based on 12 sessions

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A photographer will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?

(A) 5
(B) 6
(C) 9
(D) 24
(E) 36

Well, this has been discussed before, however people just give some examples , can someone explain any formular to solve this problem in an easy way???

like 3P3, or 3C3 to calculate ways to arrange people.
[Reveal] Spoiler: OA
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Status: Quant 50+?
Joined: 02 Feb 2011
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Concentration: Strategy, Finance
Schools: Tuck '16, Darden '16
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Re: A very very difficult math [#permalink]

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24 Aug 2011, 07:53
Not really an exact formula for it.

1 has to be bottom left and 6 has to be top right. Once you fill in slot two and three on the bottom row you have no choices for slot 4 and 5 on the top row (they fall into place). Now you only have two slots to play with in order to see the number of combos.

Should be easy to find 123456 124356 125346 134256 135246 in 30 seconds
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Joined: 21 Aug 2011
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Re: A very very difficult math [#permalink]

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24 Aug 2011, 18:00
You are wrong!!!!

It should be 6. Brother~

eragotte wrote:
Not really an exact formula for it.

1 has to be bottom left and 6 has to be top right. Once you fill in slot two and three on the bottom row you have no choices for slot 4 and 5 on the top row (they fall into place). Now you only have two slots to play with in order to see the number of combos.

Should be easy to find 123456 124356 125346 134256 135246 in 30 seconds
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Re: A very very difficult math [#permalink]

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25 Aug 2011, 05:08
Jasonammex wrote:
A photographer will arrange 6 people of 6 different heights for photograph by placing them in two rows of three so that each person in the first row is standing in front of someone in the second row. The heights of the people within each row must increase from left to right, and each person in the second row must be taller than the person standing in front of him or her. How many such arrangements of the 6 people are possible?

(A) 5
(B) 6
(C) 9
(D) 24
(E) 36

Well, this has been discussed before, however people just give some examples , can someone explain any formular to solve this problem in an easy way???

like 3P3, or 3C3 to calculate ways to arrange people.

Jasonammex is banned permanently for continuously creating a new thread with a question that's already discussed, despite multiple warnings. Also, the user creates a new user-id as soon as he/she is banned.
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Re: A very very difficult math   [#permalink] 25 Aug 2011, 05:08
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A very very difficult math

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