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A wheel that has a radius of 24 rotates 270 degrees. How

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A wheel that has a radius of 24 rotates 270 degrees. How [#permalink]

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05 May 2006, 22:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A wheel that has a radius of 24 rotates 270 degrees. How long did an edge point move?
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Re: Movement of a wheel [#permalink]

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17 May 2006, 17:35
getzgetzu wrote:
A wheel that has a radius of 24 rotates 270 degrees. How long did an edge point move?

a correction:

= (270/360) 2 pi (24)
= 36 pi

i should take a break for at least a week.....

Last edited by Professor on 17 May 2006, 19:25, edited 1 time in total.
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17 May 2006, 19:17
36Pi.

2*pi*24*3/4=36*pi
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17 May 2006, 19:23
Diameter = pi * 24* 2 = 48pi

This is equivalent to 360 degress rotation.

So 270 degrees will give you 270/360 * 48pi = 36pi
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Re: Movement of a wheel [#permalink]

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17 May 2006, 19:24
Professor wrote:
getzgetzu wrote:
A wheel that has a radius of 24 rotates 270 degrees. How long did an edge point move?

= (270/360) pi (24)^2
= (3) pi (24x6)
= 432 pi

Prof, you've gone for area instead of diameter
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Re: Movement of a wheel [#permalink]

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17 May 2006, 19:28
ywilfred wrote:
Professor wrote:
getzgetzu wrote:
A wheel that has a radius of 24 rotates 270 degrees. How long did an edge point move?

= (270/360) pi (24)^2
= (3) pi (24x6)
= 432 pi

Prof, you've gone for area instead of diameter

i was wonding why people make mistakes. now i realize why i make mistakes..

yes i went after area instead of perimeter.

Last edited by Professor on 18 May 2006, 04:14, edited 1 time in total.
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17 May 2006, 19:36
yea 36 pi looks good
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19 May 2006, 00:43
circumference - 2piR = 48pi
therefore the wheel moves 48pi in 360 deg
Hence it will move 270/360 * 48pi = 36 pi in 270 deg
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19 May 2006, 01:31
For 1 rotation ie. 360 degrees, the wheel moves 2*pi*r .
For 270 degrees it moves (270*48*pi)/360 = 36 pi
19 May 2006, 01:31
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