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A wildlife preserve is being planned for 3000 rhinoceroses.

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GMAT Club Legend
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A wildlife preserve is being planned for 3000 rhinoceroses. [#permalink] New post 22 Sep 2004, 12:35
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A wildlife preserve is being planned for 3000 rhinoceroses. The preserve is to contain a total of 10000 acres of watering area, plus 100 acres of grazing area for each rhinoceros. If the number of rhinoceroses is expected to increase by 10 percent, how many thousands acres should the preserve have in order to provide for the increased population?

A) 340
B) 330
C) 320
D) 310
E) 300

I added answer choices :)
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Paul


Last edited by Paul on 22 Sep 2004, 13:13, edited 1 time in total.
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 [#permalink] New post 22 Sep 2004, 13:02
using proportions I come up with 31,000 additional acres needed for a 10% increase.
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Re: PS Rhinoceroses [#permalink] New post 22 Sep 2004, 14:15
Paul wrote:
A wildlife preserve is being planned for 3000 rhinoceroses. The preserve is to contain a total of 10000 acres of watering area, plus 100 acres of grazing area for each rhinoceros. If the number of rhinoceroses is expected to increase by 10 percent, how many thousands acres should the preserve have in order to provide for the increased population?

A) 340
B) 330
C) 320
D) 310
E) 300

I added answer choices :)


A
Based on 3000 Rs we need 10K+100*3K acres
if pop increases by 10 percent -> we have 3.3K Rs
Hence Acres -> 10K+100*3.3K=340K
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 [#permalink] New post 22 Sep 2004, 19:27
The answer is 330K land + 10 K for watering area = 340K

What is the original answer?
GMAT Club Legend
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 [#permalink] New post 22 Sep 2004, 22:20
10,000 water area for 3000 rhinos, so each rhino takes --10/3 acres of watering area
plus 100 acres of grazing area for each rhino

increase by 10% = 300 more rhinos which would require an extra

watering area = 300*10/3 = 1000
grazing area = 300*100 = 30,000

Total = 30,100

D is the answer
GMAT Club Legend
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 [#permalink] New post 22 Sep 2004, 22:30
sorry, reposting again. made a mistake earlier..

10,000 water area for 3000 rhinos, so each rhino takes --10/3 acres of watering area
plus 100 acres of grazing area for each rhino

increase by 10% = 300 more rhinos which would require an extra

watering area = 300*10/3 = 1000 acres
grazing area = 300*100 = 30,000

Total = 30,100

Add this back to the original

10,000 + (3000*100) = 310,000 acres

Total would be ~340 thousand acres.

A should be the answer.
  [#permalink] 22 Sep 2004, 22:30
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A wildlife preserve is being planned for 3000 rhinoceroses.

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