Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 May 2015, 04:08

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A woman sold 100 oranges at $12.10, some at the rate of 3  Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Director Joined: 07 Jun 2004 Posts: 614 Location: PA Followers: 3 Kudos [?]: 275 [4] , given: 22 A woman sold 100 oranges at$12.10, some at the rate of 3 [#permalink]  26 Jul 2010, 07:39
4
This post received
KUDOS
4
This post was
BOOKMARKED
00:00

Difficulty:

75% (hard)

Question Stats:

66% (03:17) correct 34% (03:04) wrong based on 202 sessions
A woman sold 100 oranges at $12.10, some at the rate of 3 for 35 cents and the rest at 7 for 85 cents. How many were sold at the first rate? A. 45 B. 21 C. 9 D. 15 E. 12 [Reveal] Spoiler: OA _________________ If the Q jogged your mind do Kudos me : ) Manager Joined: 02 Apr 2010 Posts: 103 Followers: 5 Kudos [?]: 98 [11] , given: 18 Re: Oranges sold at different rates [#permalink] 26 Jul 2010, 08:58 11 This post received KUDOS 1 This post was BOOKMARKED This can be solved like a classical mixture problem but numbers are awkward to deal with. It's easier to just look at the answer choices. You know that a multiple of 3 oranges has to be sold at the first rate, and a multiple of 7 at the second rate. You simple subtract the answer choices for the first rate from 100 and check whether the remainder (i.e. the number of oranges sold at the second rate) is a multiple of 7. 100 - 45 = 55 => not a multiple of 7 so exclude 100 - 21 = 79 => not a multiple of 7 so exclude 100 -9 = 91 => a multiple of 7 so keep 100 - 15 = 85 => not a multiple of 7 so exclude 100 - 12 = 88 => not a multiple of 7 so exclude Hence, answer choice 9 is correct. Senior Manager Status: mba here i come! Joined: 07 Aug 2011 Posts: 271 Location: Pakistan Concentration: Strategy, Marketing GMAT 1: 680 Q46 V37 GMAT 2: Q V Followers: 32 Kudos [?]: 780 [5] , given: 48 Re: Oranges sold at different rates [#permalink] 29 Feb 2012, 09:03 5 This post received KUDOS $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ solve and you'll get x = 9 _________________ press +1 Kudos to appreciate posts Senior Manager Joined: 10 Nov 2010 Posts: 268 Location: India Concentration: Strategy, Operations GMAT 1: 520 Q42 V19 GMAT 2: 540 Q44 V21 WE: Information Technology (Computer Software) Followers: 5 Kudos [?]: 91 [0], given: 22 Re: Oranges sold at different rates [#permalink] 15 Mar 2012, 20:18 $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ Can you pls explain the Right hand side of equation. Won't it be 12.10 _________________ The proof of understanding is the ability to explain it. Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 5449 Location: Pune, India Followers: 1331 Kudos [?]: 6773 [3] , given: 177 Re: Oranges sold at different rates [#permalink] 15 Mar 2012, 21:45 3 This post received KUDOS Expert's post GMATD11 wrote: $$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$ Can you pls explain the Right hand side of equation. Won't it be 12.10 The equation equates the total selling price. He gets$12.10 i.e. 1210 cents.
If he sold x oranges for 35/3 cents and (100-x) for 85/7 cents, this is a total of
(35/3) * x + (85/7) * (100-x) cents. You equate cents to cents.

Also, you can use the weighted average formula here:

w1/w2 = (85/7 - 121/10)/(121/10 - 35/3) = 9/91

Total 9+91 is 100. So he sells 9 oranges at 35 for 3 and 91 oranges at 85 for 7.
_________________

Karishma
Veritas Prep | GMAT Instructor
My Blog

Veritas Prep GMAT course is coming to India. Enroll in our weeklong Immersion Course that starts March 29!

Veritas Prep Reviews

Intern
Joined: 12 Aug 2012
Posts: 6
Followers: 0

Kudos [?]: 0 [0], given: 18

Re: Oranges sold at different rates [#permalink]  16 Aug 2012, 23:47
GMATD11 wrote:
$$\frac{35}{3}x+\frac{85}{7}(100-x)=1210$$

Can you pls explain the Right hand side of equation.
Won't it be 12.10

Hi,

Because we are taking all the values in cents so we have converted $12.10 into cents which is 1210 cents. as 1 cent =0.01 Dollar Hope this helps. Try and fail but never fail to try. GMAT Club Legend Joined: 09 Sep 2013 Posts: 4757 Followers: 294 Kudos [?]: 52 [0], given: 0 Re: A woman sold 100 oranges at$12.10, some at the rate of 3 [#permalink]  29 Sep 2013, 07:23
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Manager
Joined: 23 May 2013
Posts: 127
Followers: 1

Kudos [?]: 32 [0], given: 110

Re: A woman sold 100 oranges at $12.10, some at the rate of 3 [#permalink] 01 Oct 2013, 04:31 for such question need a will power to take on some random complicated numbers. i derived the equation but goofed up with the numbers _________________ “Confidence comes not from always being right but from not fearing to be wrong.” GMAT Club Legend Joined: 09 Sep 2013 Posts: 4757 Followers: 294 Kudos [?]: 52 [0], given: 0 Re: A woman sold 100 oranges at$12.10, some at the rate of 3 [#permalink]  02 May 2015, 00:35
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Manager
Joined: 27 Dec 2013
Posts: 162
Followers: 0

Kudos [?]: 28 [0], given: 55

Re: A woman sold 100 oranges at $12.10, some at the rate of 3 [#permalink] 02 May 2015, 08:14 simple question.... killer calculation.. WOW... rxs0005 wrote: A woman sold 100 oranges at$12.10, some at the rate of 3 for 35 cents and the rest at 7 for 85 cents. How many were sold at the first rate?

A. 45
B. 21
C. 9
D. 15
E. 12

_________________

Kudos to you, for helping me with some KUDOS.

Re: A woman sold 100 oranges at $12.10, some at the rate of 3 [#permalink] 02 May 2015, 08:14 Similar topics Replies Last post Similar Topics: 3 A woman is planning a trip that involves 3 connecting trains 3 13 Jan 2014, 12:07 If x = (-100)^1/3 * (100)^3 0 02 Sep 2013, 02:14 Prepare some Orange juice 2 25 Mar 2010, 21:55 1 Jacob purchased 100 boxes of oranges at$8.00 per box. He 1 09 Oct 2008, 05:07
Of the 25 cars sold at a certain dealership yesterday, some 5 09 Sep 2007, 15:25
Display posts from previous: Sort by

# A woman sold 100 oranges at \$12.10, some at the rate of 3

 Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.