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Re: A wrapping paper has dimensions 1 yard by 7 yards. What is [#permalink]
I get D

Area of the sheet of paper = 21*3=63 = Surface area of cube

6s^2 = 63

s^2~9

s^3~27
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Re: A wrapping paper has dimensions 1 yard by 7 yards. What is [#permalink]
Hi

I dont think we can make either of the following assumptions:
(a) edge of the cube in feet is an integer
(b) 6s^2 = 63 => s = 3

If we don't make these assumptions:

6s^2 = 63
=> s^2 = 10.5
=> volume = s^3 = 10.5 ^ (3/2) = 34 sq feet

Thoughts?
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Re: A wrapping paper has dimensions 1 yard by 7 yards. What is [#permalink]
ssumitsh wrote:
Hi

I dont think we can make either of the following assumptions:
(a) edge of the cube in feet is an integer
(b) 6s^2 = 63 => s = 3

If we don't make these assumptions:

6s^2 = 63
=> s^2 = 10.5
=> volume = s^3 = 10.5 ^ (3/2) = 34 sq feet

Thoughts?



I agree. I did it the same way.

I have seen lately a number of questions with wrong OAs (not necessarily this one). I would suggest posting next to these kinds of OAs which the poster is not sure about words like 'OA but not sure!'

Many times it happen that the questions are wrongly worded, OAs are incorrect, or both.

This will help us focus on the concept rather than try to fit our concepts to the answer choices.



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