Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: DS problem solving [#permalink]
01 Apr 2008, 22:03

young_gun wrote:

AB and BA are 2-digits integers and AB*BA=CDE, where CDE is a 3-digits integer. What is AB? 1). A=E 2). A=C

we know AB and BA are two digit integers so 0 cannot be any of the digit. also we know CDE is a 3 digit integer so it is < than 1000 but > than 121. so:-

i. digits can only be 1, 2, 3, 4, 5, and 6. ii. 1000 > CDE > 121.

from 1: AB can be of any value from 11, 12, 13, 14, 15, 16, 21, 31 41, 51, and 61. any value of AB results in A=E if unit digit of AB is 1. so nsf. from 2: again AB can be of any value from 11, 12, 13, 14, 15, 16, 21, 31 41, 51, and 61. but to have A=C, AB must be 21.

if AB is 13, ABxBA = 403. so C=4, which is not equal to A or 3.

Re: DS problem solving [#permalink]
02 Apr 2008, 07:53

how do you know AB and BA are not something like 11?

stem doesnt explicitly say that A and B are different..

GMAT TIGER wrote:

young_gun wrote:

AB and BA are 2-digits integers and AB*BA=CDE, where CDE is a 3-digits integer. What is AB? 1). A=E 2). A=C

we know AB and BA are two digit integers so 0 cannot be any of the digit. also we know CDE is a 3 digit integer so it is < than 1000 but > than 121. so:-

i. digits can only be 1, 2, 3, 4, 5, and 6. ii. 1000 > CDE > 121.

from 1: AB can be of any value from 11, 12, 13, 14, 15, 16, 21, 31 41, 51, and 61. any value of AB results in A=E if unit digit of AB is 1. so nsf. from 2: again AB can be of any value from 11, 12, 13, 14, 15, 16, 21, 31 41, 51, and 61. but to have A=C, AB must be 21.

if AB is 13, ABxBA = 403. so C=4, which is not equal to A or 3.

Re: DS problem solving [#permalink]
02 Apr 2008, 10:48

GMAT TIGER wrote:

young_gun wrote:

AB and BA are 2-digits integers and AB*BA=CDE, where CDE is a 3-digits integer. What is AB? 1). A=E 2). A=C

we know AB and BA are two digit integers so 0 cannot be any of the digit. also we know CDE is a 3 digit integer so it is < than 1000 but > than 121. so:-

i. digits can only be 1, 2, 3, 4, 5, and 6. ii. 1000 > CDE > 121.

from 1: AB can be of any value from 11, 12, 13, 14, 15, 16, 21, 31 41, 51, and 61. any value of AB results in A=E if unit digit of AB is 1. so nsf. from 2: again AB can be of any value from 11, 12, 13, 14, 15, 16, 21, 31 41, 51, and 61. but to have A=C, AB must be 21.

if AB is 13, ABxBA = 403. so C=4, which is not equal to A or 3.

Hello everyone! Researching, networking, and understanding the “feel” for a school are all part of the essential journey to a top MBA. Wouldn’t it be great... ...

I have not posted in more than a month! It has been a super busy period, wrapping things up at Universal Music, completing most of the admin tasks in preparation for Stanford...