Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 28 Jul 2016, 15:44

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

AB CD + AAA = where AB and CD are two-digit numbers

Author Message
Director
Joined: 30 Nov 2006
Posts: 591
Location: Kuwait
Followers: 14

Kudos [?]: 237 [0], given: 0

AB CD + AAA = where AB and CD are two-digit numbers [#permalink]

Show Tags

06 May 2007, 03:39
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

AB
CD +
AAA =

where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined
Senior Manager
Joined: 03 May 2007
Posts: 272
Followers: 1

Kudos [?]: 10 [0], given: 0

Show Tags

06 May 2007, 22:55
ok that's how i solved this problem

AAA is 111 (we can't use 222 because 222/2 is a three digit number)

so now we know that 111=1B+CD B can be 3 to 8 => CD is 98 to 93

C=9

Director
Joined: 26 Feb 2006
Posts: 904
Followers: 4

Kudos [?]: 96 [0], given: 0

Show Tags

11 May 2007, 12:37
Mishari wrote:
AB
CD +
AAA =

where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined

is not it too easy to guess AAA as 111 cux no 2 digit integers sum up more than 198. therefore AAA cannot be other than 111 and to have 111, C must be 9.
VP
Joined: 08 Jun 2005
Posts: 1146
Followers: 6

Kudos [?]: 164 [0], given: 0

Show Tags

11 May 2007, 12:57

The max value that AAA can get is when

AB = 99 and CD = 99

AB+CD = 198

so A has to be 1. when A=1 then AAA=111

1B+CD = 111

If C = 8 then the max value is 19+89 = 108 which is less then 111

so C has to be 9 !

13+98 = 111 or 18+93 = 111

Display posts from previous: Sort by