Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 02 Jul 2016, 01:08

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# AB CD+ AAA= where AB and CD are two-digit numbers and

Author Message
Director
Joined: 30 Nov 2006
Posts: 591
Location: Kuwait
Followers: 14

Kudos [?]: 228 [0], given: 0

AB CD+ AAA= where AB and CD are two-digit numbers and [#permalink]

### Show Tags

06 May 2007, 03:37
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

AB
CD+
AAA=

where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined
Current Student
Joined: 28 Dec 2004
Posts: 3385
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 14

Kudos [?]: 241 [0], given: 2

### Show Tags

10 Sep 2007, 14:40
Get 9 too

we know that A is 1...

so

1B
CD
111

try a couple of number 15 for AB and 96 for CD

you can vary B and D but C is always 9..
VP
Joined: 10 Jun 2007
Posts: 1459
Followers: 7

Kudos [?]: 208 [0], given: 0

### Show Tags

10 Sep 2007, 15:57
Mishari wrote:
AB
CD+
AAA=

where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined

I think 9
A=1 since anything less than 100 add together will be less than 200

So if B+D <= 9, then
B+D = 1
1+C = 11
C=10

if B+D >9, then
B+D = 11
1+1+C=11
C=9
Director
Joined: 12 Jun 2006
Posts: 532
Followers: 2

Kudos [?]: 80 [0], given: 1

### Show Tags

10 Sep 2007, 16:50
Mishari wrote:
AB
CD+
AAA=

where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined
everyone else seemed to get 9. C too

18 + 93 = 111
VP
Joined: 10 Jun 2007
Posts: 1459
Followers: 7

Kudos [?]: 208 [0], given: 0

### Show Tags

10 Sep 2007, 18:48
Kalyan wrote:
bkk145/ fresinha12, why is A=1 only?

Because if you add two digit numbers, the result must be less than 200
you also know that the result has 3 digits. Therefore, it must be that
100 <= AAA <=199
Therefore, A can only be 1.
CEO
Joined: 29 Mar 2007
Posts: 2583
Followers: 19

Kudos [?]: 345 [0], given: 0

### Show Tags

10 Sep 2007, 19:32
Mishari wrote:
AB
CD+
AAA=

where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined

Aha finally got it.

Since AB and CD are two digit numbers and AAA is a three digit number. AAA has to be less than 200. Ex/ 99+99=198. So since the last digit of AAA has to be 1 then all the A's are 1.

So the new problem looks like this:

1B
+CD
111

To get 1 from B+D, B+D has to either equal 11 or 1 (0+1). In this case only 11 works b/c C can't be 10.

It doesnt matter what the values of B and D are, but just that they equal 11. Since there is a carry over of 1. C must be equal to 9. Since 9+1+1=11.

The numbers could look like this.

15
+96
111

Ans D
Display posts from previous: Sort by