Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

I attached the diagram, which was missing in initial post.

Attachment:

Trianlge.PNG [ 1.74 KiB | Viewed 10739 times ]

In the triangle above, is x > 90?

(1) a^2 + b^2 <15 (2) c > 4

Each statement alone is clearly insufficient. When taken together: If angle x were 90 degrees than we would have a^2+b^2=4^2, since a^2+b^2<15<16 then angle x must be greater than 90 degrees (c^2 is greater than a^2+b^2 then the angel opposite c must be greater than 90).

c^2 is greater than a^2+b^2 then the angel opposite c must be greater than 90

Hi Guys,

Would anyone be able to explain why the angle is greater than 90 if c^2 is greater than a^2+b^2?

Serge.

If c^2 were equal to a^2+b^2 then we would have a^2+b^2=c^2, which would mean that angle x is 90 degrees. Now, since c^2 is more than a^2+b^2, then angle x, which is opposite c, must be more than 90 degrees: try to increase side c and you'll notice that angle x will increase too.

ABC with a trainagle with three sides abc and one of the angle is x

In the triangle above, is x > 90? (1) a2 + b2 <15 (2) c> 4 A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

E for me.
(1) don't know c
INSUFFICIENT

(2) Only know c
INSUFFICIENT

Together, if a^2 + b^2 < 15
We know that at least one angle in the triangle is greater than 90 if a=2.99, b=3.99, c=5. But other angles are less than 90. We don't know where x is; thus, insufficient.

ABC with a trainagle with three sides abc and one of the angle is x

In the triangle above, is x > 90? (1) a2 + b2 <15> 4 A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient. B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient. C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient. D. EACH statement ALONE is sufficient. E. Statements (1) and (2) TOGETHER are NOT sufficient.

Note that for a right triangle, c^2 = a^2+b^2, where c is the length of the side opposite the right angle C.

We don't have to know which angle is x. Question is asking, whether any of the angle in the triangle is greater than 90.

since c^2 > a^2 + b^2 , we know tht angle opposite to side c will be greater than 90.

So, both the statements are required to answer the question. My choice is C.

Together, we are told that the triangle is obtuse- one interior angle is greater than 90º. However, we don't know which which angle is being asked about

We don't have to know which angle is x. Question is asking, whether any of the angle in the triangle is greater than 90.

since c^2 > a^2 + b^2 , we know tht angle opposite to side c will be greater than 90.

So, both the statements are required to answer the question. My choice is C.

Its not asking whether any of the angle in the triangle is greater than 90.
It is asking that one of the angle is x, Is x > 90? Means one perticular angle.N we dont know which is the one ?

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4 [#permalink]

Show Tags

17 Feb 2012, 01:27

Whenever Asqr + Bsqr Is equal to Csqr than angle X is 90 degrees Look at both options carefully ,

Asqr + Bsqr Is less than 15 and C greater than 4 means any value more than 4 for c and will automatically increase angle X bcoz as C increases angle 8 increases

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4 [#permalink]

Show Tags

26 Jan 2013, 20:15

Bunuel wrote:

I attached the diagram, which was missing in initial post.

Attachment:

Trianlge.PNG

In the triangle above, is x > 90?

(1) a^2 + b^2 <15 (2) c > 4

Each statement alone is clearly insufficient. When taken together: If angle x were 90 degrees than we would have a^2+b^2=4^2, since a^2+b^2<15<16 then angle x must be greater than 90 degrees (c^2 is greater than a^2+b^2 then the angel opposite c must be greater than 90).

Answer: C.

Hope it helps.

What would happen is the statement was c>3? how would this question be framed such that the angle could be always below 90 degrees. Since in this particular question the solution will always be greater, what would be the opposite case?
_________________

Click +1 Kudos if my post helped...

Amazing Free video explanation for all Quant questions from OG 13 and much more http://www.gmatquantum.com/og13th/

GMAT Prep software What if scenarios http://gmatclub.com/forum/gmat-prep-software-analysis-and-what-if-scenarios-146146.html

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4 [#permalink]

Show Tags

26 Jan 2013, 20:50

fozzzy wrote:

Bunuel wrote:

I attached the diagram, which was missing in initial post.

Attachment:

Trianlge.PNG

In the triangle above, is x > 90?

(1) a^2 + b^2 <15 (2) c > 4

Each statement alone is clearly insufficient. When taken together: If angle x were 90 degrees than we would have a^2+b^2=4^2, since a^2+b^2<15<16 then angle x must be greater than 90 degrees (c^2 is greater than a^2+b^2 then the angel opposite c must be greater than 90).

Answer: C.

Hope it helps.

What would happen is the statement was c>3? how would this question be framed such that the angle could be always below 90 degrees. Since in this particular question the solution will always be greater, what would be the opposite case?

If you reverse the values, such as: (1) a^2 + b^2 >16 (2) c < 4 You would get a case where angle x would be less than 90, provided a triangle is still formed. (Note that a+b will tend to be bigger and C tends to be smaller in this option)
_________________

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4 [#permalink]

Show Tags

24 Feb 2013, 20:46

1

This post was BOOKMARKED

smily_buddy wrote:

Attachment:

Trianlge.PNG

In the triangle above, is x > 90?

(1) a^2 + b^2 <15 (2) c > 4

If a^2 + b^2 = c^2 then x= 90. But , as given in st2, minimum value of C = 5, then C^2 = 25. It means a^2 + b^2 < c^2.Thus, x <90. Therefore, C.
_________________

Re: ABC with a trainagle with three sides abc and one of the [#permalink]

Show Tags

24 Feb 2013, 22:14

abhi47 wrote:

E is the correct answer. Both statements are insufficient.

from one, possible values of (a,b) = (1,2) or (1,3) or (2,3) or (2,2) from 2nd, given that c>4 Property of triangle is = sum of two sides > third side therefor only possible values are a= 2, b=3 and c = 5 or a = 3 and b = 2 and c =5 since a^2 + b ^2 = c^2 hence it is a right angle triangle hence both conditions required to answer so option(c)

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4 [#permalink]

Show Tags

29 Sep 2014, 23:29

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4 [#permalink]

Show Tags

01 Oct 2015, 16:41

a^2+b^2 = c^2 then angle opposite of c is right angle triangle a^2+b^2 < c^2 then angle opposite of c is greater than 90 a^2+b^2 > c^2 then angle opposite of c is less than 90

Using the above logic, we can make of use of both the statements to answer the question. Hence answer is C.

gmatclubot

Re: In the triangle above, is x > 90? (1) a^2 + b^2 < 15 (2) c>4
[#permalink]
01 Oct 2015, 16:41

Happy New Year everyone! Before I get started on this post, and well, restarted on this blog in general, I wanted to mention something. For the past several months...

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Happy 2017! Here is another update, 7 months later. With this pace I might add only one more post before the end of the GSB! However, I promised that...

The words of John O’Donohue ring in my head every time I reflect on the transformative, euphoric, life-changing, demanding, emotional, and great year that 2016 was! The fourth to...