harshavmrg wrote:
burp wrote:
ABCD is a quadrilateral. A rhombus is a quadrilateral whose sides are all congruent. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater: ABCD or BCEF ?
(1) ABCD is a square.
(2) BCEF is not a square.
Hi All,
I am having difficulty in understanding the proble,
1. ABCD is a square....As per defination Rhombus also has the same side. I am confused on how to tell the diagonal lengths with the help of sides of a rhombus. I think this is not sufficient.
2. BCEF not a square, no info about ABCD..hence not sufficient.
Together..we know ABCD is a square and BECF is not, but it is still rhombus...hence it is not sufficient together too...so E
Can any expert help us understand this
Dear Harsh,
Q. is : ABCD is a quadrilateral. A rhombus is a quadrilateral whose sides are all congruent. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater: ABCD or BCEF ?
(1) ABCD is a square.
(2) BCEF is not a square.
This question can be very easily solved with a property of a quadilateral:-
A square has a larger area than any other quadrilateral with the same perimeterNow for (1) ABCD is a square, but we know nothing about BCEF. Another property is
If the diagonals of a rhombus are equal, then that rhombus must be a square. Now as we see, we only know that BCEF is a Rhombus, we know nothing about the angle. Hence (1) insufficient.
(2) Insufficient
(1) + (2), here we get that BCEF is not a square, hence clearly Area ABCD > Area BCEF Sufficient
Hence C
Hope I am clear
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34% (01:55) correct
