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ABCD is a quadrilateral. A rhombus is a quadrilateral whose [#permalink]
29 Dec 2010, 07:08

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This post was BOOKMARKED

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A

B

C

D

E

Difficulty:

45% (medium)

Question Stats:

38% (01:46) correct
62% (00:59) wrong based on 68 sessions

ABCD is a quadrilateral. A rhombus is a quadrilateral whose sides are all congruent. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater: ABCD or BCEF ?

Re: Area of which is greater ?? [#permalink]
29 Dec 2010, 09:30

Expert's post

Let's do it step by step.

1. How are ABCD and BCEF connected? There is only a common side BC. All other tree sides of ABCD can be of any size and the area of ABCD can be (0, inf). BCEF is a rhombus and its area can be (0, BC^2] (BC^2 included).

2. Statement 1. In other words, area of ABCD is BC^2 that can be greater or equal to the area of BCEF (0, BC^2]

3. Statement 2. So, area of BCEF can't be BC^2 and we have (0, BC^2) possible range for the area. it's still not enough as the area ABCD can be (0, inf)

4. Statements 1&2. The area of ABCD is BC^2 and the area of BCEF can be (0, BC^2) or always lesser than the area of ABCD. Sufficient.

Re: ABCD is a quadrilateral. A rhombus is a quadrilateral whose [#permalink]
01 Apr 2012, 04:04

Hi

Iam new to GMAT club and was going through this problem.I think A should be the answer to this problem.Logic given below.

1.Statement 1 says ABCD is a square. Now for all quadrilaterals with given perimeter square has the greatest area .Perimeter of square ABCD and BCEF =4a where a=length of one side.(Square and rhombus share a common side ,so lenght of side of Rhombus is also a).So applying the above property area of square greater than rhombus.

2.) Statement 2 says that BCEF is not a square, doesnt provide any useful infromation.Hence clearly not sufficient.

Re: ABCD is a quadrilateral. A rhombus is a quadrilateral whose [#permalink]
02 Apr 2012, 21:15

burp wrote:

ABCD is a quadrilateral. A rhombus is a quadrilateral whose sides are all congruent. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater: ABCD or BCEF ?

(1) ABCD is a square. (2) BCEF is not a square.

Hi All,

I am having difficulty in understanding the proble,

1. ABCD is a square....As per defination Rhombus also has the same side. I am confused on how to tell the diagonal lengths with the help of sides of a rhombus. I think this is not sufficient.

2. BCEF not a square, no info about ABCD..hence not sufficient.

Together..we know ABCD is a square and BECF is not, but it is still rhombus...hence it is not sufficient together too...so E

Can any expert help us understand this _________________

Regards, Harsha

Note: Give me kudos if my approach is right , else help me understand where i am missing.. I want to bell the GMAT Cat

Re: ABCD is a quadrilateral. A rhombus is a quadrilateral whose [#permalink]
04 Jul 2012, 05:48

harshavmrg wrote:

burp wrote:

ABCD is a quadrilateral. A rhombus is a quadrilateral whose sides are all congruent. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater: ABCD or BCEF ?

(1) ABCD is a square. (2) BCEF is not a square.

Hi All,

I am having difficulty in understanding the proble,

1. ABCD is a square....As per defination Rhombus also has the same side. I am confused on how to tell the diagonal lengths with the help of sides of a rhombus. I think this is not sufficient.

2. BCEF not a square, no info about ABCD..hence not sufficient.

Together..we know ABCD is a square and BECF is not, but it is still rhombus...hence it is not sufficient together too...so E

Can any expert help us understand this

Dear Harsh,

Q. is : ABCD is a quadrilateral. A rhombus is a quadrilateral whose sides are all congruent. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater: ABCD or BCEF ?

(1) ABCD is a square. (2) BCEF is not a square.

This question can be very easily solved with a property of a quadilateral:- A square has a larger area than any other quadrilateral with the same perimeter Now for (1) ABCD is a square, but we know nothing about BCEF. Another property is If the diagonals of a rhombus are equal, then that rhombus must be a square. Now as we see, we only know that BCEF is a Rhombus, we know nothing about the angle. Hence (1) insufficient. (2) Insufficient (1) + (2), here we get that BCEF is not a square, hence clearly Area ABCD > Area BCEF Sufficient Hence C Hope I am clear

If you like my solution kindly give me Kudos _________________

_______________________________________________________________________________________________________________________________ If you like my solution kindly reward me with Kudos.

ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
04 Aug 2013, 08:18

ABCD is a quadrilateral. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater ABCD or BCEF ?

(1) ABCD is a square. (2) BCEF is not a square.

Solution: From (1), ABCD is a square. So its area= BC × BC And we know from the question that BCEF is a rhombus which shares a side with ABCD, so the area of the rhombus = BC × FJ (from diagram). [The area of rhombus = area of two equal triangles inside it = ½ BC× FJ + ½ BC× FJ = BC× FJ ]

Here all sides of the two quadrilaterals are equals for sharing one same side.

But a rhombus has a less altitude than a square has because of its angles. So clearly BC>FJ, Consequently area of ABCD > area of BCEF

Statement (1) alone is sufficient.

Statement (2) is not necessary at all, because from the question we already know BCEF is a rhombus. Its not sufficient at all.

So the answer is (A).

From my point of view the answer is (A), but in the Nova’s data sufficiency prep course book (Author: jeff kolby) i find the answer is (C).

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
04 Aug 2013, 08:49

a square is a rhombus too ( vice a versa is not true) unless we know that rhombus is not square, we cannot tell area is greater or equal. So if it is square then area is equal but if not square then square > rhombus.

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
04 Aug 2013, 11:58

rhombus has maximum area when it is a square otherwise in all other cases the area of the rhombus will be less than the square with same side length.

as square comes under category of a RHOMBUS so we need to consider that case also

statement 1: ABCD is a square===>in this situation there are 2 cases case 1:when rhombus is a square ===>in this case the area of both ABCD and CDEF will be same. case 2:when rhombus is not a square===.in this case area of ABCD will be MORE THAN CDEF. hence insufficient

statement 2: CDEF is not a square this alone doesnt gives any information about ABCD.hence insufficient.

combining : now we know CDEF is not a square hence area ABCD will be greater than CDEF. HENCE C

hope this helps _________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
04 Aug 2013, 13:03

AMITAGARWAL2 wrote:

a square is a rhombus too ( vice a versa is not true) unless we know that rhombus is not square, we cannot tell area is greater or equal. So if it is square then area is equal but if not square then square > rhombus.

So C

how can square be a rhombus. All the angles are 90 degree in square but not even one in the rhombus !!! we know it clearly...... with equal sides as square, a rhombus must have less altitude than that of the square due to the angles... can you explain it? _________________

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
05 Aug 2013, 10:42

Asifpirlo wrote:

AMITAGARWAL2 wrote:

a square is a rhombus too ( vice a versa is not true) unless we know that rhombus is not square, we cannot tell area is greater or equal. So if it is square then area is equal but if not square then square > rhombus.

So C

how can square be a rhombus. All the angles are 90 degree in square but not even one in the rhombus !!! we know it clearly...... with equal sides as square, a rhombus must have less altitude than that of the square due to the angles... can you explain it?

A rhombus is a quadrilateral with all 4 sides equal in length. A square is a type of rhombus just as a rhombus is a type of quadrilateral.

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
05 Aug 2013, 10:45

Observer wrote:

Asifpirlo wrote:

AMITAGARWAL2 wrote:

a square is a rhombus too ( vice a versa is not true) unless we know that rhombus is not square, we cannot tell area is greater or equal. So if it is square then area is equal but if not square then square > rhombus.

So C

how can square be a rhombus. All the angles are 90 degree in square but not even one in the rhombus !!! we know it clearly...... with equal sides as square, a rhombus must have less altitude than that of the square due to the angles... can you explain it?

A rhombus is a quadrilateral with all 4 sides equal in length. A square is a type of rhombus just as a rhombus is a type of quadrilateral.

yes its a proven theory that a square is a rhombus too despite the differences in angles...... _________________

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
05 Aug 2013, 12:51

Asifpirlo wrote:

yes its a proven theory that a square is a rhombus too despite the differences in angles......

Sorry misunderstood your question. I don't know if that diagram you posted is your own or is from the book you got the problem from, but it's misleading. Without B you do not know whether BCEF is a square or not. The diagram suggests we know that BCEF is a rhombus and not a square from the stem but only B gives that information.

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
05 Aug 2013, 13:12

Observer wrote:

Asifpirlo wrote:

yes its a proven theory that a square is a rhombus too despite the differences in angles......

Sorry misunderstood your question. I don't know if that diagram you posted is your own or is from the book you got the problem from, but it's misleading. Without B you do not know whether BCEF is a square or not. The diagram suggests we know that BCEF is a rhombus and not a square from the stem but only B gives that information.

the question tells BCEF is a rhombus and accordint to it i draw the diagram... _________________

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm [#permalink]
09 Dec 2013, 18:03

ABCD is a quadrilateral. BCEF is a rhombus and shares a common side with the quadrilateral ABCD. The area of which one is greater ABCD or BCEF ?

(1) ABCD is a square.

Tells us that ABCD is a square and that BCEF shares side measurements with ABCD. A rhombus will have a smaller than a square with the same side lengths. However, BCEF could be a square as well because a square is also a rhombus. We cannot be 100% sure. Not Sufficient.

(2) BCEF is not a square.

Tells us nothing about ABCD and very little about BCEF. Not Sufficient.

1+2) Tells us that ABCD is a square and that BCEF has the same side measurements but is not a square. Therefore, the area of ABCD is greater than the area of BCEF. SUFFICIENT

gmatclubot

Re: ABCD is a quadrilateral. BCEF is a rhombus and shares a comm
[#permalink]
09 Dec 2013, 18:03