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Re: ABCD is a rectangle inscribed in a circle. If the length of AB is thr [#permalink]

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17 Apr 2011, 14:20

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Area cannot be 3.2 because area of circle is pi r^2 i.e. 3.14, so rule out III Even if the length is very close to the diameter i.e. 1 approx, width has to be 1/100 to make the area .01 - possible similarly 1.9 is also possible. =>D
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Re: ABCD is a rectangle inscribed in a circle. If the length of AB is thr [#permalink]

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01 May 2011, 20:10

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area of rectangle = l*b

diagonal is 2 also d (diagonal) = sqrt (l^2 + b^2) l*b = l * sqrt (2 -l^2) area is positive therefore (2-l^2) >0 i.e sqrt2>l similarly sqrt2>b therefore area = l.b <sqrt 2.sqrt2 = 1.4 *1.4 = 1.96 therefore D is correct.

Re: ABCD is a rectangle inscribed in a circle. If the length of AB is thr [#permalink]

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01 May 2011, 22:29

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Max area of the rectangle possible when diagonal = diameter = 2 Hence, l^2 + b^2 = 4. Implies l and b < 1.5 each. Also, area of circle = 3.14 * 1^2 = 3.14. hence options C and E POE. Now, 0<l <1.5 and 0<b<1.5. Thus area can be 0.01 and 1.9 both. Hence D.
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Re: ABCD is a rectangle inscribed in a circle. If the length of AB is thr [#permalink]

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25 Apr 2015, 21:53

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Re: ABCD is a rectangle inscribed in a circle. If the length of AB is thr [#permalink]

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17 Oct 2015, 00:27

15 seconds solution the max area of a rectangle could be the area of squire that can be inscribed in circle with vertices on edges of circle , hence max area could be 2*2 / 2 as 2 is the max length of dignol of squire, hence D

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Re: ABCD is a rectangle inscribed in a circle. If the length of AB is thr
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17 Oct 2015, 00:27

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