gsr wrote:

If there is nothing mentioned about x, for x=0, this is false. For -ve integer values of x, it is true and for positive values it is true.

Can you please post the whole question?

This is the original question:

Find the solution set for the following inequalities |3x-2|<=|2x-5|

The first step of the explanatory answer for this question from 4gmat ebook is squaring both sides to get rid of the absolute value sign.

(3x-2)^2<=(2x-5)^2

However, I read once that

**Quote:**

"Another way to eliminate an absolute value is to square both sides of the equation. Taking the absolute value makes things non-negative, and squaring makes things non-negative. So, if you square something, you no longer need to take its absolute value. However, be careful when squaring both sides of an equation as this can lead to extraneous solutions."

from

http://www.richland.edu/james/lecture/m116/prerequisites.html
Thus, I would like to know if there's an approach other than squaring both sides.

Let me know if you want to see the OE.