Abs Value Equation : Quant Question Archive [LOCKED]
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Abs Value Equation

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Intern
Joined: 07 Jul 2005
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16 Jul 2005, 06:42
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Okay, I will post without the answer so everyone can practice. (Will post answer later.) I apologize if I don't know the proper area of the forum for this, but I need help understanding how to set this up. So if you could all explain your logic, that would be great.

|6+x| = 2x+1, solve for x
Senior Manager
Joined: 04 May 2005
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16 Jul 2005, 16:57
if x>=-6, the equation becomes:

6+x = 2x+1 => x = 5

if x<-6, the equation becomes:

-6-x = 2x+1 => x = -7/3 which contradicts with the assumption
x < -6

therefore, x = 5 is the only solution
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16 Jul 2005, 17:58
|6+x| = 2x+1, solve for x

6 + x = 2x + 1 = 6-1 = 2x - x = 5 = x

-6 - x = 2x + 1 = -7 = 3x = -7/3 = x
16 Jul 2005, 17:58
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