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Absolute fundamentals

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Director
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Absolute fundamentals [#permalink] New post 31 Jul 2010, 03:30
Can some one explain in steps how to solve the absolute equations algebraically and when do we flip the inequality sign


EG : | x + 3 | > -10

how do we come up with the solutions for this inequality
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Manager
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Re: Absolute fundamentals [#permalink] New post 31 Jul 2010, 07:38
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Try to remember these fundamentals, they will help you open the modulus:
#1
if you have |quantity| < 4
--> -4 < quantity < 4.
#2
if you have quantity^2 < 16
--> -4 < quantity < 4.

#3
if you have |quantity| > 4
--> quantity > 4 OR quantity < -4.
#4
if you have quantity^2 > 16
--> quantity > 4 OR quantity < -4.

So according to these, your question becomes type 3:
i.e: x+3> -10 or x+3< 10 i.e x>-13 or x<7

You should be checking the Math book post on Absolute values to get a better understnading.
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Director
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Re: Absolute fundamentals [#permalink] New post 31 Jul 2010, 08:42
Thanks how do we handle this with multiple

| x + 3 | > | x - 14 | + 1

how many solutions does the above inequality have
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Re: Absolute fundamentals [#permalink] New post 31 Jul 2010, 13:31
I think, your question above is incorrect.
Nonetheless, I would advise to check more about Absolute values here:
math-absolute-value-modulus-86462.html

If the above post helped then would appreciate Kudos
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Re: Absolute fundamentals   [#permalink] 31 Jul 2010, 13:31
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