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Absolutely no idea about this [#permalink] New post 24 Jun 2006, 21:22
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 [#permalink] New post 24 Jun 2006, 21:48
I am getting C simply by multiply 16 x 360 and 18 x 360.

Is this the OA?
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 [#permalink] New post 25 Jun 2006, 16:41
(1) 16 feet/s = 10.9 mi/hr
So, distance travelled in 1/2 hr = 5.45miles

since speed was greater than 16 feet/s, distance travelled was > 5.45 miles - not sufficient

(2) 18 feet/s = 12.3 mi/hr
So, distance travelled in 1/2 hr = 6.15 miles

since speed was less than 18 feet/s, distance travelled was < 6.15 miles - not sufficient

Taking together: 5.45 < distance < 6.15

Hence E
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 [#permalink] New post 25 Jun 2006, 22:12
Good explanation. We don't get any distinct value from I and II. Combining the two results we get 28800 < d < 32400 (in feet). We need to know whether d = 31680 feet? (d = distance covered in 1/2 an hour). So E.
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 [#permalink] New post 26 Jun 2006, 00:53
Quote:
Good explanation. We don't get any distinct value from I and II. Combining the two results we get 28800 < d < 32400 (in feet). We need to know whether d = 31680 feet? (d = distance covered in 1/2 an hour). So E.


Did the same way. I vote for E too.
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 [#permalink] New post 26 Jun 2006, 02:38
the answer is E.
A,B and D can be easily ruled out.
C can be ruled out because the speed can be any value from 16.1 to 17.9
hence different answers for different values...:)
  [#permalink] 26 Jun 2006, 02:38
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