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Manager
Joined: 12 Apr 2006
Posts: 218
Location: India
Followers: 1

Kudos [?]: 24 [0], given: 17

00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
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Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 26 [0], given: 0

I am getting C simply by multiply 16 x 360 and 18 x 360.

Is this the OA?
Director
Joined: 16 Aug 2005
Posts: 947
Location: France
Followers: 1

Kudos [?]: 10 [0], given: 0

(1) 16 feet/s = 10.9 mi/hr
So, distance travelled in 1/2 hr = 5.45miles

since speed was greater than 16 feet/s, distance travelled was > 5.45 miles - not sufficient

(2) 18 feet/s = 12.3 mi/hr
So, distance travelled in 1/2 hr = 6.15 miles

since speed was less than 18 feet/s, distance travelled was < 6.15 miles - not sufficient

Taking together: 5.45 < distance < 6.15

Hence E
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Manager
Joined: 09 Apr 2006
Posts: 173
Location: Somewhere in Wisconsin!
Followers: 1

Kudos [?]: 2 [0], given: 0

Good explanation. We don't get any distinct value from I and II. Combining the two results we get 28800 < d < 32400 (in feet). We need to know whether d = 31680 feet? (d = distance covered in 1/2 an hour). So E.
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Zooroopa

Intern
Joined: 04 May 2006
Posts: 49
Followers: 0

Kudos [?]: 0 [0], given: 0

Quote:
Good explanation. We don't get any distinct value from I and II. Combining the two results we get 28800 < d < 32400 (in feet). We need to know whether d = 31680 feet? (d = distance covered in 1/2 an hour). So E.

Did the same way. I vote for E too.

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Manager
Joined: 22 May 2006
Posts: 71
Followers: 1

Kudos [?]: 0 [0], given: 0

A,B and D can be easily ruled out.
C can be ruled out because the speed can be any value from 16.1 to 17.9
hence different answers for different values...
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