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According to directions on a can of frozen orange juice

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According to directions on a can of frozen orange juice [#permalink] New post 29 Jul 2006, 10:50
According to directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings og orange juice?

1) 25
2) 34
3) 50
4) 67
5) 100
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Re: Orange juice [#permalink] New post 29 Jul 2006, 12:26
4 cans of orange juice need 1 can of concentrate.
200 cans 6 oz. of orange juice need 50 cans 6 oz. concentrate.
so 12 oz. concentrate = 50/2 = 25 cans
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 [#permalink] New post 30 Jul 2006, 09:21
I got the same answer as above but here's how I arrived at it:

You need 200 servings
1 serving equal 6 ounces
Therefore you need 1200 oz

Now, 1 can = 12 oz of concentrate
For each can, I need 3 cans of water
Therefore, the total ounces are 12 oz concentrate + (3)(12 oz) water
The total equals 48 oz of OJ that is made per can of concentrate.

You need a total of 1200 oz. There are 48oz of OJ created to one can of concentrate. So the ratio is 1200/x = 48/1. Cross multiply and you get 48x = 1200. x = 25
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 [#permalink] New post 07 Aug 2006, 17:09
200 * 6 - 1200 total ounces of OJ..

Ratio is 1:3 This 900 water and 300 concentrate.

Thus 300/12 oz cans = 25 final answer
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Re: Orange juice [#permalink] New post 11 Aug 2006, 19:31
jaynayak wrote:
According to directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings og orange juice?

1) 25
2) 34
3) 50
4) 67
5) 100


Tricky
x=# of 12 ounce cans reqd
3x=# of 12 ounce cans of H2O reqd
Total needed = 200*6 ounce

x(12) + 3x(12) = 200*6
48x= 200*6
x=25
Hence A
Re: Orange juice   [#permalink] 11 Aug 2006, 19:31
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