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# According to the formula F=9/5 (C) +32, if the temperature

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According to the formula F=9/5 (C) +32, if the temperature [#permalink]  27 Sep 2013, 22:25
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According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A) 9
B) 15
C) 47
D) 48 3/5
E) 59
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Re: According to the formula F=9/5 (C) +32, [#permalink]  27 Sep 2013, 22:52
Expert's post
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

$$F_i = \frac{9}{5}* (C_i) +32$$

$$F_i+27= \frac{9}{5}* (C_f) +32$$

On Subtracting, we get$$27 = \frac{9}{5}* (C_f-C_i) \to (C_f-C_i) = 3*5 = 15$$

B.
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Re: According to the formula F=9/5 (C) +32, [#permalink]  28 Sep 2013, 03:09
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usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

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Kudos [?]: 47109 [1] , given: 7104

Re: According to the formula F=9/5 (C) +32, [#permalink]  28 Sep 2013, 03:11
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Re: According to the formula F=9/5 (C) +32, [#permalink]  01 Oct 2013, 09:54
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

I dont understand why you only multiplied 5/9 by 27. what about F-32?
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Posts: 28717
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Kudos [?]: 47109 [0], given: 7104

Re: According to the formula F=9/5 (C) +32, [#permalink]  02 Oct 2013, 02:35
Expert's post
usre123 wrote:
Bunuel wrote:
usre123 wrote:
According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 27, by how much does the temperature in degrees Celsius (C) increase?

A)9
B)15
C)47
D) 48 3/5
E) 59

You can plug in values.

C = 5/9*(F-32)

F=32 --> C=0;
F=32+27=59 --> C=5/9*27=15.

Increase = 15 degrees.

I dont understand why you only multiplied 5/9 by 27. what about F-32?

If F=59 --> C = 5/9*(F-32) = 5/9*(59-32) = 5/9*27 = 15.

Does this make sense?
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Re: According to the formula F=9/5 (C) +32, if the temperature [#permalink]  25 Dec 2014, 05:24
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Re: According to the formula F=9/5 (C) +32, if the temperature   [#permalink] 25 Dec 2014, 05:24
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