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# According to the incomplete table above, if each of the 6

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Senior Manager
Joined: 30 May 2005
Posts: 281
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Kudos [?]: 9 [0], given: 0

According to the incomplete table above, if each of the 6 [#permalink]  15 Jun 2005, 13:02
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100% (01:01) correct 0% (00:00) wrong based on 4 sessions
According to the incomplete table above, if each of the 6 teams in the league played each of the other teams exactly twice and there were no ties, how many games did team X win? (Only 2 teams play in a game.)
(A) 4
(B) 5
(C) 6
(D) 8
(E) 10
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Director
Joined: 03 Nov 2004
Posts: 870
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Kudos [?]: 18 [0], given: 0

[#permalink]  15 Jun 2005, 18:16
I will go with C

The number of games played between each other is 6C2 = 15
Since it is played twice, it will be 2 * 15 = 30
The total number of games played is 30, the table shows that 22 games have been won by A,B,C,D & E put together, so the number of games won by X = 30 -24 = 6
[#permalink] 15 Jun 2005, 18:16
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# According to the incomplete table above, if each of the 6

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