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# After winning 50 percent of the first 20 games it played,

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Director
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After winning 50 percent of the first 20 games it played, [#permalink]

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04 Aug 2010, 04:34
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45% (medium)

Question Stats:

63% (02:12) correct 37% (00:51) wrong based on 145 sessions

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After winning 50 percent of the first 20 games it played, Team Red won all of the remaining games it played. What was the total number of games that Team Red won?

(1) Team Red played 25 games altogether
(2) Team Red won 60 percent of all the games it played

OPEN DISCUSSION OF THIS QUESTION IS HERE: after-winning-50-percent-of-the-first-20-games-it-played-te-167045.html
[Reveal] Spoiler: OA

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Re: After winning 50 percent of the first 20 games it played, [#permalink]

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04 Aug 2010, 04:47
Problem 1

Let p = percentage of games won and W1,W2 be the first 20 games won, the second X games won and T1 and T2 the first and second total number of games played.
P = (W1+W2) / (T1+T2) is percentage of games won

We know W1=10, T1=20, W2=T2

Statement 1
T1+T2 = 25,
Thus T2=W2=5 and W1+W2 = (10+5) which is sufficient to answer the question

Statement 2
P=60%

0.6 = (10+W2) / (20+T2) hence W2=2+0.6T2 and W2=2+0.6W2 and W2 = 5
W1+W2 = 10+5 thus it is sufficient to answer the question
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Re: After winning 50 percent of the first 20 games it played, [#permalink]

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04 Aug 2010, 09:40
rxs0005 wrote:
After winning 50 percent of the first 20 games it played, Team Red won all of the remaining games it played. What was the total number of games that Team Red won?

(1) Team Red played 25 games altogether
(2) Team Red won 60 percent of all the games it played

1) total games played = 25; so 25 includes first 20 games of which team red won 50% meaning 10 and team red won all the remaining games they played - which means of the 5 remaining games (25-20) they won all 5; so total games won 10+5 = 15;;;; hence sufficient

2) we can set up the eqn as follows: assume total games played by team red = $$x$$
so $$10 + (x-20) = (0.6).x$$
solving for $$x = 25$$

So D ..... each stmt is sufficient.

however usually on the gmat both choices lead to the same answer. I dont know why this one is leading to two diff answers...
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Re: After winning 50 percent of the first 20 games it played, [#permalink]

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04 Aug 2010, 14:03
rxs0005 wrote:
After winning 50 percent of the first 20 games it played, Team Red won all of the remaining games it played. What was the total number of games that Team Red won?

(1) Team Red played 25 games altogether
(2) Team Red won 60 percent of all the games it played

Statement 1:

Total games = 25

50% of 20 = 10 + (25-20) = 15 games.

Sufficient.

Statement 2:

Let the total games = X.

Number of games won = $$10 + (X-20) = 0.6X$$

$$X-20 = 0.6X$$

$$0.4X = 20$$

$$X = \frac{20}{0.4} = 50$$

So the number of games won = 10 + 30 = 40

Sufficient.

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Re: After winning 50 percent of the first 20 games it played, [#permalink]

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04 Aug 2015, 22:18
1) team red won 50% of 20+ (25-20) so, sufficient

2)let total matches played=x
matches won=0.6x
0.6x=50%of 20+(x-20)
so, x=25..........sufficient

so, (D)
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Re: After winning 50 percent of the first 20 games it played, [#permalink]

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16 Aug 2015, 11:08
Expert's post
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After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.

(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.

(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.

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OPEN DISCUSSION OF THIS QUESTION IS HERE: after-winning-50-percent-of-the-first-20-games-it-played-te-167045.html
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Re: After winning 50 percent of the first 20 games it played,   [#permalink] 16 Aug 2015, 11:08
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