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After winning 50 percent of the first 20 games it played, Te

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After winning 50 percent of the first 20 games it played, Te [#permalink] New post 04 Feb 2014, 00:54
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The Official Guide For GMAT® Quantitative Review, 2ND Edition

After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

(1) Team A played 25 games altogether.
(2) Team A won 60 percent of all the games it played.

Data Sufficiency
Question: 75
Category: Arithmetic Percents
Page: 158
Difficulty: 600


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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 04 Feb 2014, 00:55
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After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.

(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.

(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.

Answer: D.

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after-winning-80-of-his-first-40-matches-igby-won-129062.html
after-winning-50-percent-of-the-first-30-matches-she-played-129132.html
after-winning-50-percent-of-the-first-x-games-it-played-149675.html
after-winning-30-percent-of-the-first-50-games-it-played-142267.html
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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 04 Feb 2014, 03:12
Ans D.

From S1: if team A won 10 games out of first 20 and all the remaining games and we're given the no of games it played in total,we can find out the no. of games it won ie 10+ 5=15.Sufficient.

From S2: let total no. of games = x
we're given: 0.6x = 10 +(x-20)
we can find out x to find out how many did A win. Sufficient.
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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 04 Feb 2014, 23:05
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For the first 20 games, the no. of games won = 50% of 20 = (1/2)*20 = 10;
Let us assume the remaining no. of games played = x, as the no. of games played is the same as the no. of games won.

We need to find the total no. of games Team A won: 10 + x

We can rephrase the question further: what is the total no. of games played? or what is the remaining no. of games played?

Statement (1): Sufficient, since we know the total no. of games played: 10 + 5 = 15;

Statement (2): 60% of all games: 60% of (20 + x)
Also, we can arrive at the following equation: 10 + x = 60% of (20 + x);
10 + x = 12 + 0.6x;
0.4x = 2;
x = 5;

So, the total no. of games won = 10 + x = 10 + 5 =15;

Ans is (D).
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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 08 Feb 2014, 04:51
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SOLUTION

After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.

(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.

(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.

Answer: D.

Similar questions to practice:
after-winning-80-percent-of-the-fi-rst-40-games-it-played-129338.html
a-chess-player-won-25-percent-of-the-first-20-games-152608.html
after-winning-80-of-his-first-40-matches-igby-won-129062.html
after-winning-50-percent-of-the-first-30-matches-she-played-129132.html
after-winning-50-percent-of-the-first-x-games-it-played-149675.html
after-winning-30-percent-of-the-first-50-games-it-played-142267.html
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Collection of Questions:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 09 Aug 2014, 07:50
Hi Bunuel, Please correct numbering to Q#75 here -
"Data Sufficiency
Question: 70
Category: Arithmetic Percents
Page: 158
Difficulty: 600"
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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 12 Aug 2014, 06:29
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Re: After winning 50 percent of the first 20 games it played, Te [#permalink] New post 10 Sep 2015, 06:01
[quote="Bunuel"]SOLUTION

After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.

(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.

(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.


A Little explanation:

After 20 games:
Team A has won 10 games

After 25 games:
Suppose team A won 15 games in total, which is possibly sufficed by (1) Team A played 25 games altogether.

Now coming to (2), to win 60% of all the games, there are multiple possible answers
For total 30 games, team A may win 18 games, which is 60% of total games played,
For total 35 games, team A may win 21 games, which is also 60% of total games played,
For total 40 games, team A may win 24 games, which is also 60% of total games played.

It doesn't give the exact number of games that team A could have won.
Hence option (2) is not sufficient.

Please clarify
Re: After winning 50 percent of the first 20 games it played, Te   [#permalink] 10 Sep 2015, 06:01
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