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After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

(1) Team A played 25 games altogether. (2) Team A won 60 percent of all the games it played.

Data Sufficiency Question: 75 Category:Arithmetic Percents Page: 158 Difficulty: 600

Each week we'll be posting several questions from The Official Guide For GMAT® Quantitative Review, 2ND Edition and then after couple of days we'll provide Official Answer (OA) to them along with a slution.

We'll be glad if you participate in development of this project: 1. Please provide your solutions to the questions; 2. Please vote for the best solutions by pressing Kudos button; 3. Please vote for the questions themselves by pressing Kudos button; 4. Please share your views on difficulty level of the questions, so that we have most precise evaluation.

Re: After winning 50 percent of the first 20 games it played, Te [#permalink]
04 Feb 2014, 00:55

Expert's post

SOLUTION

After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.

(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.

(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.

Re: After winning 50 percent of the first 20 games it played, Te [#permalink]
04 Feb 2014, 03:12

Ans D.

From S1: if team A won 10 games out of first 20 and all the remaining games and we're given the no of games it played in total,we can find out the no. of games it won ie 10+ 5=15.Sufficient.

From S2: let total no. of games = x we're given: 0.6x = 10 +(x-20) we can find out x to find out how many did A win. Sufficient.

Re: After winning 50 percent of the first 20 games it played, Te [#permalink]
04 Feb 2014, 23:05

1

This post received KUDOS

For the first 20 games, the no. of games won = 50% of 20 = (1/2)*20 = 10; Let us assume the remaining no. of games played = x, as the no. of games played is the same as the no. of games won.

We need to find the total no. of games Team A won: 10 + x

We can rephrase the question further: what is the total no. of games played? or what is the remaining no. of games played?

Statement (1): Sufficient, since we know the total no. of games played: 10 + 5 = 15;

Statement (2): 60% of all games: 60% of (20 + x) Also, we can arrive at the following equation: 10 + x = 60% of (20 + x); 10 + x = 12 + 0.6x; 0.4x = 2; x = 5;

So, the total no. of games won = 10 + x = 10 + 5 =15;

Re: After winning 50 percent of the first 20 games it played, Te [#permalink]
08 Feb 2014, 04:51

Expert's post

SOLUTION

After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?

The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.

(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.

(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.

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