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Re: After winning 50 percent of the first 20 games it played, Te [#permalink]
10 Sep 2015, 06:01
After winning 50 percent of the first 20 games it played, Team A won all of the remaining games it played. What was the total number of games that Team A won?
The team won 50 percent of the first 20 games --> the team won 10 out of 20 games.
(1) Team A played 25 games altogether. Team A won (25 - 20) + 10 = 15 games. Sufficient.
(2) Team A won 60 percent of all the games it played --> 0.6*(20 + x) = 10 + x --> x= 5 --> the total number of games the team won is 10 + 5 = 15. Sufficient.
A Little explanation:
After 20 games: Team A has won 10 games
After 25 games: Suppose team A won 15 games in total, which is possibly sufficed by (1) Team A played 25 games altogether.
Now coming to (2), to win 60% of all the games, there are multiple possible answers For total 30 games, team A may win 18 games, which is 60% of total games played, For total 35 games, team A may win 21 games, which is also 60% of total games played, For total 40 games, team A may win 24 games, which is also 60% of total games played.
It doesn't give the exact number of games that team A could have won. Hence option (2) is not sufficient.
Re: After winning 50 percent of the first 20 games it played, Te
10 Sep 2015, 06:01