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After winning 50 percent of the first 30 matches she played [#permalink]
15 Mar 2012, 13:15

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After winning 50 percent of the first 30 matches she played, Hortense won all of her remaining matches. How many total matches did she win?

(1) Hortense won 75 percent of the matches she played. (2) If Hortense had won 50 percent of the total number of matches she played, she would have lost 15 more total matches.

Re: After winning 50 percent of the first 30 matches she played [#permalink]
15 Mar 2012, 23:57

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This post received KUDOS

Expert's post

After winning 50 percent of the first 30 matches she played, Hortense won all of her remaining matches. How many total matches did she win?

(1) Hortense won 75 percent of the matches she played. Say # of remaining matches is R: 30*0.5+R*1=(30+R)*0.75, we have only one unknown R, hence we can solve for it. Sufficient.

(2) If Hortense had won 50 percent of the total number of matches she played, she would have lost 15 more total matches --> Hortense won 50% of his first 30 matches and 100% of the remaining matches, in order to win 50% of total matches she should have won 50% of the remaining matches (instead of 100%, so 50% less). So 50% losses in the remaining matches (R) result in 15 more losses: 0.5*R=15 --> R=30 --> total matches won: 30*0.5+30*1=45. Sufficient.

Re: After winning 50 percent of the first 30 matches she played [#permalink]
19 Sep 2013, 22:32

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Re: After winning 50 percent of the first 30 matches she played [#permalink]
04 Jun 2014, 23:41

After winning 50 percent of the first 30 matches she played, Hortense won all of her remaining matches. How many total matches did she win?

(1) Hortense won 75 percent of the matches she played. Say # of remaining matches is R: 30*0.5+R*1=(30+R)*0.75, we have only one unknown R, hence we can solve for it. Sufficient.

(2) If Hortense had won 50 percent of the total number of matches she played, she would have lost 15 more total matches --> Hortense won 50% of his first 30 matches and 100% of the remaining matches, in order to win 50% of total matches she should have won 50% of the remaining matches (instead of 100%, so 50% less). So 50% losses in the remaining matches (R) result in 15 more losses: 0.5*R=15 --> R=30 --> total matches won: 30*0.5+30*1=45. Sufficient.

Hi There - Is there any way you can explain the second point again please

Re: After winning 50 percent of the first 30 matches she played [#permalink]
05 Jun 2014, 00:47

Expert's post

Raghunathnallu wrote:

After winning 50 percent of the first 30 matches she played, Hortense won all of her remaining matches. How many total matches did she win?

(1) Hortense won 75 percent of the matches she played. Say # of remaining matches is R: 30*0.5+R*1=(30+R)*0.75, we have only one unknown R, hence we can solve for it. Sufficient.

(2) If Hortense had won 50 percent of the total number of matches she played, she would have lost 15 more total matches --> Hortense won 50% of his first 30 matches and 100% of the remaining matches, in order to win 50% of total matches she should have won 50% of the remaining matches (instead of 100%, so 50% less). So 50% losses in the remaining matches (R) result in 15 more losses: 0.5*R=15 --> R=30 --> total matches won: 30*0.5+30*1=45. Sufficient.

Hi There - Is there any way you can explain the second point again please

Please elaborate what exactly was confusing there. Thank you.

Re: After winning 50 percent of the first 30 matches she played [#permalink]
06 Jun 2014, 01:35

1) she won 75% of total matches means she did not win 25% of matches , which is 50% of first 30 matches(=> 15 matches), since she won all the remaining matches . let total matches be x , 25% of x=15 x=60 , hence sufficient

2) if for 50% win she lost 15 more matches, total match not won = 30 , total matches = 2(30) = 60 hence, sufficient

gmatclubot

Re: After winning 50 percent of the first 30 matches she played
[#permalink]
06 Jun 2014, 01:35

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