After winning 80% of his first 40 matches, Igby won 50

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After winning 80% of his first 40 matches, Igby won 50 [#permalink]

14 Mar 2012, 04:03

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Question Stats:

35% (02:56) correct

64% (01:59) wrong

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After winning 80% of his first 40 matches, Igby won 50 percent of his remaining matches. How many total matches did he win?

(1) If Igby had won 50 percent of the total number of matches he played, he would have lost 12 more total matches.
(2) If Igby had won 80% of the total number of matches he played, he would have won 18 more total matches.

To me it seems that both statements contradict each other. The first one basically claims that he has only played 40 total games, while the second claims that he has played 62.5 matches.

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Re: After winnig 80% of his first 40 matches... [#permalink]

14 Mar 2012, 04:47

Let remaining matches be x

So Total matches won = 0.8 * 40 + 0.5 * x
The number of matches not won = 0.2 * 40 + Number of Matches Lost + Number of Matches drawn

1) 0.5 (40 + x) = 0.2 * 40 + Number of matches lost + 12

So x can’t be found, we don’t know the number of matches lost, because from the remaining %age (50% of x), there is no breakup for number of matches drawn.

2) 0.8(40 + x) = 0.8 * 40 + 0.5 * x + 18
So x can be found
Answer - B
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Re: After winning 80% of his first 40 matches, Igby won 50 [#permalink]

14 Mar 2012, 05:33

You really do not need any formula for this question. Also I can see no contraction between the statements.

After winning 80% of his first 40 matches, Igby won 50 percent of his remaining matches. How many total matches did he win?

(1) If Igby had won 50 percent of the total number of matches he played, he would have lost 12 more total matches --> Igby won 80% of his first 40 matches and 50% of the remaining matches, in order to win 50% of total matches he should have won 50% of his first 40 matches too (instead of 80%, so 30% less), which would have resulted in 0.3*40=12 more losses. So, this statement gives us the info we could deduce ourselves. Not sufficient.

(2) If Igby had won 80% of the total number of matches he played, he would have won 18 more total matches --> with the same logic he should have won 80% of the remaining matches, (instead of 50%, so 30% more). So 30% more winnings in the remaining matches (X) result in 18 more wins: 0.3*x=18 --> x=60 --> total matches won: 0.8*40+0.5*60=62. Sufficient.

Answer: B.
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total number of matches [#permalink]

01 Apr 2012, 16:51

After winning 80 percent of the first 40 matches he played, Igby won 50 percent of his remaining matches. How many total matches did he win?

(1) If Igby had won 50 percent of the total number of matches he played, he would have lost 12 more total matches.
(2) If Igby had won 80 percent of the total number of matches he played, he would have won 18 more total matches.

Let say total matches played be x

0.8(40) = 32 matches won from 1st 40 matches and therefore lost = 8. Matches remaining (x-40) ------------(1)

I am struggling to take this question forward. Can you please help?
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Re: total number of matches [#permalink]

01 Apr 2012, 16:53

enigma123 wrote:

Merging similar topics. Please ask if anything remains unclear.
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Re: total number of matches [#permalink] 01 Apr 2012, 16:53

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After winning 80% of his first 40 matches, Igby won 50

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After winning 80% of his first 40 matches, Igby won 50

After winning 80% of his first 40 matches, Igby won 50

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