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Airplanes A and B traveled the same 360-mile route

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Airplanes A and B traveled the same 360-mile route [#permalink] New post 02 Mar 2012, 08:28
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Question Stats:

95% (02:05) correct 5% (00:43) wrong based on 76 sessions
Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?

(A) 2

(B) \(2\frac{1}{3}\)

(C) \(2\frac{1}{2}\)

(D) \(2\frac{2}{3}\)

(E) 3

I agree with the OA.
However, something that I don't understand is why cannot analyze it in this way:
The question says that airplane B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, right?
The OE says that, based on this info, that airplane A travels at 180 mph, so airplane B travels at 120 mph (1/3 slower).
Why cannot "1/3 slower" mean this?
A ---- 180 miles / 1 hour
B ---- 180 miles /[(4/3)*1hour]
The answer would be different.

Please, your comments.

Source: http://www.gmathacks.com
[Reveal] Spoiler: OA

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Re: Airplanes A and B traveled the same 360-mile route [#permalink] New post 02 Mar 2012, 08:47
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metallicafan wrote:
Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?
(A) 2
(B) \(2\frac{1}{3}\)
(C) \(2\frac{1}{2}\)
(D) \(2\frac{2}{3}\)
(E) 3

I agree with the OA.
However, something that I don't understand is why cannot analyze it in this way:
The question says that airplane B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, right?
The OE says that, based on this info, that airplane A travels at 180 mph, so airplane B travels at 120 mph (1/3 slower).
Why cannot "1/3 slower" mean this?
A ---- 180 miles / 1 hour
B ---- 180 miles /[(4/3)*1hour]
The answer would be different.

Please, your comments.

Source: http://www.gmathacks.com


The red part should be 3/2.

I'd approach this question in different manner and hope that it helps you to understand the question better.

Since B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, then the speed of B was \(\frac{2}{3}\) of that of A (\(x-\frac{1}{3}x=\frac{2}{3}x\)). So, airplane B would need \(\frac{3}{2}\) times more time to cover the same distance: \(2*\frac{3}{2}=3\) hours. That's because time*rate=distance, so if you decrease rate 2/3 times you'll need 3/2 times as many hours to cover the same distance.

Answer: E.
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Re: Airplanes A and B traveled the same 360-mile route [#permalink] New post 31 Dec 2013, 09:41
metallicafan wrote:
Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?

(A) 2

(B) \(2\frac{1}{3}\)

(C) \(2\frac{1}{2}\)

(D) \(2\frac{2}{3}\)

(E) 3

I agree with the OA.
However, something that I don't understand is why cannot analyze it in this way:
The question says that airplane B traveled at an average speed that was \(\frac{1}{3}\) slower than the average speed of airplane A, right?
The OE says that, based on this info, that airplane A travels at 180 mph, so airplane B travels at 120 mph (1/3 slower).
Why cannot "1/3 slower" mean this?
A ---- 180 miles / 1 hour
B ---- 180 miles /[(4/3)*1hour]
The answer would be different.

Please, your comments.

Source: http://www.gmathacks.com


Easy question

A traveled at 180mph

2/3*180 = 120mph

Hence B made the trip in 360/120 = 3 hours

Or recall that as distance is constant, then B will need 3/2 as much time as A to cover same distance

So it will give 3 as well
Hope it helps
Cheers!
J :)
Re: Airplanes A and B traveled the same 360-mile route   [#permalink] 31 Dec 2013, 09:41
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Airplanes A and B traveled the same 360-mile route

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