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# Airplanes A and B traveled the same 360-mile route

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Airplanes A and B traveled the same 360-mile route [#permalink]

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02 Mar 2012, 09:28
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Difficulty:

5% (low)

Question Stats:

95% (02:12) correct 5% (00:52) wrong based on 95 sessions

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Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?

(A) 2

(B) $$2\frac{1}{3}$$

(C) $$2\frac{1}{2}$$

(D) $$2\frac{2}{3}$$

(E) 3

I agree with the OA.
However, something that I don't understand is why cannot analyze it in this way:
The question says that airplane B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, right?
The OE says that, based on this info, that airplane A travels at 180 mph, so airplane B travels at 120 mph (1/3 slower).
Why cannot "1/3 slower" mean this?
A ---- 180 miles / 1 hour
B ---- 180 miles /[(4/3)*1hour]

Source: http://www.gmathacks.com
[Reveal] Spoiler: OA

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Kudos [?]: 80041 [1] , given: 10025

Re: Airplanes A and B traveled the same 360-mile route [#permalink]

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02 Mar 2012, 09:47
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Expert's post
metallicafan wrote:
Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?
(A) 2
(B) $$2\frac{1}{3}$$
(C) $$2\frac{1}{2}$$
(D) $$2\frac{2}{3}$$
(E) 3

I agree with the OA.
However, something that I don't understand is why cannot analyze it in this way:
The question says that airplane B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, right?
The OE says that, based on this info, that airplane A travels at 180 mph, so airplane B travels at 120 mph (1/3 slower).
Why cannot "1/3 slower" mean this?
A ---- 180 miles / 1 hour
B ---- 180 miles /[(4/3)*1hour]

Source: http://www.gmathacks.com

The red part should be 3/2.

I'd approach this question in different manner and hope that it helps you to understand the question better.

Since B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, then the speed of B was $$\frac{2}{3}$$ of that of A ($$x-\frac{1}{3}x=\frac{2}{3}x$$). So, airplane B would need $$\frac{3}{2}$$ times more time to cover the same distance: $$2*\frac{3}{2}=3$$ hours. That's because time*rate=distance, so if you decrease rate 2/3 times you'll need 3/2 times as many hours to cover the same distance.

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Re: Airplanes A and B traveled the same 360-mile route [#permalink]

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31 Dec 2013, 10:41
metallicafan wrote:
Airplanes A and B traveled the same 360-mile route. If airplane A took 2 hours and airplane B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, how many hours did it take airplane B to travel the route?

(A) 2

(B) $$2\frac{1}{3}$$

(C) $$2\frac{1}{2}$$

(D) $$2\frac{2}{3}$$

(E) 3

I agree with the OA.
However, something that I don't understand is why cannot analyze it in this way:
The question says that airplane B traveled at an average speed that was $$\frac{1}{3}$$ slower than the average speed of airplane A, right?
The OE says that, based on this info, that airplane A travels at 180 mph, so airplane B travels at 120 mph (1/3 slower).
Why cannot "1/3 slower" mean this?
A ---- 180 miles / 1 hour
B ---- 180 miles /[(4/3)*1hour]

Source: http://www.gmathacks.com

Easy question

A traveled at 180mph

2/3*180 = 120mph

Hence B made the trip in 360/120 = 3 hours

Or recall that as distance is constant, then B will need 3/2 as much time as A to cover same distance

So it will give 3 as well
Hope it helps
Cheers!
J
Re: Airplanes A and B traveled the same 360-mile route   [#permalink] 31 Dec 2013, 10:41
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