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Al, Lew, and Karen pooled their funds to buy a gift for a

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prasannar
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Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   Updated on: 21 Mar 2008, 22:48
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Al, Lew, and Karen pooled their funds to buy a gift for a friend. Al contributed $2 less than 1/3 of the cost of the gift and Lew contributed $2 more than 1/4of the cost. If Karen contributed the remaining $15, what was the cost of the gift?

(A) $24
(B) $33
(C) $36
(D) $43
(E) $45
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C

Originally posted by prasannar on 21 Mar 2008, 21:49.
Last edited by prasannar on 21 Mar 2008, 22:48, edited 1 time in total.
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   21 Mar 2008, 22:53
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C - 36

the two guys together contribute to 7/12 (1/3 + 1/4) of the overall price, leaving 5/12 to be paid.

this 5/12 is equivalent to 15 dollars, and so the overall cost of the gift is 15*12/5 = 36
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   31 Dec 2011, 09:48
prasannar wrote:
Al, Lew, and Karen pooled their funds to buy a gift for a friend. Al contributed $2 less than 1/3 of the cost of the gift and Lew contributed $2 more than 1/4 of the cost. If Karen contributed the remaining $15, what was the cost of the gift?
(A) $24
(B) $33
(C) $36
(D) $43
(E) $45


Do the red mark portions have any impact on solving the ps?
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   01 Jan 2012, 00:22
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had it been $2 and $3 or different for each cases, it would have had impact.
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   03 Nov 2016, 00:07
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prasannar wrote:
Al, Lew, and Karen pooled their funds to buy a gift for a friend. Al contributed $2 less than 1/3 of the cost of the gift and Lew contributed $2 more than 1/4of the cost. If Karen contributed the remaining $15, what was the cost of the gift?

(A) $24
(B) $33
(C) $36
(D) $43
(E) $45


Similar question to practice: three-friends-are-buying-a-gift-for-a-friend-declan-contributes-4-dol-193481.html
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   03 Nov 2016, 08:39
prasannar wrote:
Al, Lew, and Karen pooled their funds to buy a gift for a friend. Al contributed $2 less than 1/3 of the cost of the gift and Lew contributed $2 more than 1/4of the cost. If Karen contributed the remaining $15, what was the cost of the gift?

(A) $24
(B) $33
(C) $36
(D) $43
(E) $45


A=x/3-2
L=x/4+2
K=15
all together equal to x.
x/3+x/4 + 15 = x
7x/12 +15 = x
5x/12 = 15
x = 12*15/5
x=12*3
x=36

C
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   27 Apr 2018, 10:01
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prasannar wrote:
Al, Lew, and Karen pooled their funds to buy a gift for a friend. Al contributed $2 less than 1/3 of the cost of the gift and Lew contributed $2 more than 1/4of the cost. If Karen contributed the remaining $15, what was the cost of the gift?

(A) $24
(B) $33
(C) $36
(D) $43
(E) $45


We can let the total cost of the gift = n and create the equations.

We see that:

Al contributed: (1/3)n - 2

Lew contributed: (1/4)n + 2

Karen contributed: 15

And so:

(1/3)n - 2 + (1/4)n + 2 + 15 = n

(1/3)n + (1/4)n + 15 = n

Multiplying by 12, we have:

4n + 3n + 180 = 12n

7n + 180 = 12n

180 = 5n

36 = n

Answer: C
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink] New post   21 Oct 2023, 08:12
pmenon wrote:
C - 36

the two guys together contribute to 7/12 (1/3 + 1/4) of the overall price, leaving 5/12 to be paid.

this 5/12 is equivalent to 15 dollars, and so the overall cost of the gift is 15*12/5 = 36

Be careful here I think the total equation would have taken into account that A paid (1/3)X - 2
and that L paid 1/4 * X + 2

But these in fact cancel out when you equate the 15$ to the remaining portion of the price:

15 = X - (1/3)X + 2 - (1/4)X - 2
this simplifies to 15 = x - X * 7/12
correct, but the numbers would have been different, the result wouldn't have been this
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Re: Al, Lew, and Karen pooled their funds to buy a gift for a [#permalink]
21 Oct 2023, 08:12
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