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Al, Pablo, and Marsha shared the driving on a 1,500-mile

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Al, Pablo, and Marsha shared the driving on a 1,500-mile [#permalink] New post 07 Jun 2008, 19:05
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Question Stats:

65% (02:28) correct 34% (01:20) wrong based on 148 sessions
Al, Pablo, and Marsha shared the driving on a 1,500-mile trip. Which of the three drove the greatest distance on the trip?

(1) Al drove 1 hour longer than Pablo but at an average rate of 5 miles per hour slower than Pablo.

(2) Marsha drove 9 hours and averaged 50 miles per hour.
[Reveal] Spoiler: OA

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Last edited by Bunuel on 25 Aug 2012, 01:55, edited 1 time in total.
OA added.
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Re: GmatPrep. 32.DS [#permalink] New post 08 Jun 2008, 00:17
I will go for E
(1) gives information about Al and PAblo but no relation for Marsha
Insufficient
(2) tells abt Marsho but agin no info abt Al and Pablo
togetehr also no clue
So E is the best option
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Re: Al, Pablo, and Marsha shared the driving on a 1,500-mile [#permalink] New post 25 Aug 2012, 01:42
@Bunuel,
Could you please explain why both the statements together are insufficient.
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Re: Al, Pablo, and Marsha shared the driving on a 1,500-mile [#permalink] New post 01 Aug 2013, 13:17
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Al, Pablo, and Marsha shared the driving on a 1,500-mile trip. Which of the three drove the greatest distance on the trip?

Distance = Rate*time

(1) Al drove 1 hour longer than Pablo but at an average rate of 5 miles per hour slower than Pablo.

Al Distance: (r-5)*(t+1)
INSUFFICIENT

(2) Marsha drove 9 hours and averaged 50 miles per hour.
Distance = Rate*time
Distance = 50*9
Distance = 450.

Marsha drove 450 miles meaning Al and Pablo drove a combined 950 but we still don't know who drove the most.
INSUFFICIENT

d1+d2=950
(r*t)+[(r-5)*(t+1)]=950
rt+rt+r-5t-5=950
2rt+r-5t=955

There is no further information given about d or t. Unlike other problems where it is possible to plug in other formulas to cancel out variables, plugging in formulas in here will simply lead to the introduction of new variables.
INSUFFICIENT

(E)
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Re: Al, Pablo, and Marsha shared the driving on a 1,500-mile [#permalink] New post 01 Aug 2013, 15:27
WholeLottaLove wrote:
Marsha drove 450 miles meaning Al and Pablo drove a combined950but we still don't know who drove the most.


Its these kind of mistakes which may cause to be the difference between a 750 and an average score :)
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Re: Al, Pablo, and Marsha shared the driving on a 1,500-mile [#permalink] New post 01 May 2014, 07:04
sondenso wrote:
Al, Pablo, and Marsha shared the driving on a 1,500-mile trip. Which of the three drove the greatest distance on the trip?

(1) Al drove 1 hour longer than Pablo but at an average rate of 5 miles per hour slower than Pablo.

(2) Marsha drove 9 hours and averaged 50 miles per hour.


Going by process of Elimination

Lets take (2) --> It only indicates that Marsha drove 450 km so the remaining distance of 1500 - 450 could be distributed anyway between Al and Pablo. Clearly not sufficient

Taking (1) Let speeds of Pablo = p , time = t. Alone it is clearly insufficient as there are 2 variables and one equation so multiple solutions possible.
Pooling up with (2) ,
1050 = p*t + (p -5)*(t+1)


Since this has two variables and only equation , it can infinite results so Not sufficient.


Bunuel - is my thought process correct ?
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Re: Al, Pablo, and Marsha shared the driving on a 1,500-mile [#permalink] New post 01 May 2014, 08:37
Expert's post
himanshujovi wrote:
sondenso wrote:
Al, Pablo, and Marsha shared the driving on a 1,500-mile trip. Which of the three drove the greatest distance on the trip?

(1) Al drove 1 hour longer than Pablo but at an average rate of 5 miles per hour slower than Pablo.

(2) Marsha drove 9 hours and averaged 50 miles per hour.


Going by process of Elimination

Lets take (2) --> It only indicates that Marsha drove 450 km so the remaining distance of 1500 - 450 could be distributed anyway between Al and Pablo. Clearly not sufficient

Taking (1) Let speeds of Pablo = p , time = t. Alone it is clearly insufficient as there are 2 variables and one equation so multiple solutions possible.
Pooling up with (2) ,
1050 = p*t + (p -5)*(t+1)


Since this has two variables and only equation , it can infinite results so Not sufficient.


Bunuel - is my thought process correct ?


Yes, it is.

Though notice that there are certain cases when you CAN solve one equations with two variables. For example, in cases of Diophantine equations (equations whose solutions must be integers only):

eunice-sold-several-cakes-if-each-cake-sold-for-either-109602.html
martha-bought-several-pencils-if-each-pencil-was-either-a-100204.html
a-rental-car-agency-purchases-fleet-vehicles-in-two-sizes-a-105682.html
joe-bought-only-twenty-cent-stamps-and-thirty-cent-stamps-106212.html
a-certain-fruit-stand-sold-apples-for-0-70-each-and-bananas-101966.html
joanna-bought-only-0-15-stamps-and-0-29-stamps-how-many-101743.html

Hope it helps.
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Re: Al, Pablo, and Marsha shared the driving on a 1,500-mile   [#permalink] 01 May 2014, 08:37
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Al, Pablo, and Marsha shared the driving on a 1,500-mile

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