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Re: Algebra Anyone? [#permalink]
21 Feb 2008, 11:23

(1) 10p+q - (10q+p) = 27. Simplify to get p-q = 3. Any number of solutions possible. (2) {1, 3, ..., 49}. This can be written as x = 2n-1. For n = 1, x = 1; n=2, x = 3;... n =25, x = 49.

Re: Algebra Anyone? [#permalink]
21 Feb 2008, 20:06

agree with the responses.

for a, you cant get a unique solution based on teh information given. the most we can determine is that the digits differ by 3, so you can have 41, 52,30, etc.

for b, half of the integers will be even and half will be odd...

gmatclubot

Re: Algebra Anyone?
[#permalink]
21 Feb 2008, 20:06

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