DavidArchuleta wrote:

ISBtarget wrote:

what is y?

1) cube(y)+2y = y +2*sqr(y)

2) sqr(y) = y

Taking statement 1, dividing both sides by y, we get sqr(y) - 2y +1 = 0 => (y-1)^2 = 0=> y-1 = 0 and hence y =1

Taking statement 2, dividing both sides by y, we straight away get y =1, but the OA is given as niether statement is sufficients...could some one please explain

Hey, never divide both sides for any thing that you are not sure whether or not it could be Zero. In both statements, y=1 or 0

thanks for the info

Even otherwise, take statement 1

take y out of left and right handside y ( y^2+2) = y ( 2y+1)

cancel out y on both sides , we get y^2 -2y+1 which is (y-1)^2 = 0 , which is y =1.

could you please explain