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All intelligent people are nearsighted. I am very

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All intelligent people are nearsighted. I am very [#permalink] New post 09 May 2005, 15:59
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22. All intelligent people are nearsighted. I am very nearsighted. So I must be a genius.

Which one of the following exhibits both of the logical flaws exhibited in the argument above?

(A) I must be stupid because all intelligent people are nearsighted and I have perfect eyesight.
(B) All chickens have beaks. This bird has a beak. So this bird must be a chicken.
(C) All pigs have four legs, but this spider has eight legs. So this spider must be twice as big as any pig.
(D) John is extremely happy, so he must be extremely tall because all tall people are happy.
(E) All geniuses are very nearsighted. I must be very nearsighted since I am a genius.
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 [#permalink] New post 09 May 2005, 17:00
Answer is D


Intelligent= near sight ASSUMPTION very near sight = very intelligent, genius

Tall = happy Very Tall = Very happy
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 [#permalink] New post 09 May 2005, 18:09
All I -> N
Very N -> Very I (Genius)

The flaw here is to give you a general relationship, and then reverse
the relationship illogically under an extreme circumstance.

Here, the general relationship is Intelligent -> Nearsighted (All I->N)
The author then reverse the relationship illogically (N->I, when it should be Not N -> Not I)
The extreme circumstance given is Genius (very intelligent) because he is Very nearsighted.

So now look at the answer choices:

(A) All I->N, S->P. Different logic.

(B) All C->B. B->C. Different logic.

(C) All P->4L. S->8L. S->2*P. Different logic.

(D) All T->H. John: Extemely happy -> Extremely tall. Same logic as passage.

(E) All G->V.N. I: V.N->G. Different logic

D for me.
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 [#permalink] New post 09 May 2005, 18:36
shalinikhatri wrote:
Ans B.


B only commits 1 of the 2 flaws in the original passage. There is no extreme condition given in choice (B).
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 [#permalink] New post 09 May 2005, 21:10
D

Wilfred is right. We would need to have bigger beak for the bird and a "super" chicken, so to speak, to make B correct.
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 [#permalink] New post 10 May 2005, 03:48
Dudes it has to be (D) :twisted:
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 [#permalink] New post 10 May 2005, 05:19
Those who chose B pls explain why
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 [#permalink] New post 10 May 2005, 07:49
B)...

argument: all A are B ! i am B ! so i am A !

B) all A are B ! it is B ! so it is A ! => same reasoning

D) all A are B ! he is C ! so he is D ! => not the same reasoning, because we cannot deduce that happy = extremely happy and tall = extremely tall.
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 [#permalink] New post 10 May 2005, 08:05
Christoph, it shud be "D"....argument is actually twisted it actually says

all A are B ! I am C (extreme B) ! so I must be D (extreme A)! ......"D" has the same logic. I missed this nuance in the first go as well.
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 [#permalink] New post 10 May 2005, 08:11
banerjeea_98 wrote:
Christoph, it shud be "D"....argument is actually twisted it actually says

all A are B ! I am C (extreme B) ! so I must be D (extreme A)! ......"D" has the same logic. I missed this nuance in the first go as well.


baner, you are right. thx :)
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Answer [#permalink] New post 11 May 2005, 15:26
The OA is D.
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 [#permalink] New post 12 May 2005, 20:51
Late, but D.

D can be rewritten as:

All happy people are tall. John is extremely happy, so he must be extremely tall.

which is very similiar to...

All intelligent people are nearsighted. I am very nearsighted. So I must be a genius.

Eureka!
  [#permalink] 12 May 2005, 20:51
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