All of the 540 people who attended an education convention were either teachers or administrators. There were twice as many females as males at the convention and 3 times as many teachers as administrators. If 1/3 of the administrators were males, how many of the females were teachers?
Looking for a 30-sec approach.
1. No.of people = 540
2. No of males =x, no of females = 2x
3. No of administrators=y, no of teachers = 3y
4. y/3 = male administrators and 2y/3 = female administrators
No of Female teachers?
= Number of Females - Number of Female administrators
1. x + 2x = 540 or x=180.
2. y + 3y = 540 or y=135.
Female teachers = 2x-2y/3 = 360-90=270
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