All of the bonds on a certain exchange are designated by a 3 : GMAT Problem Solving (PS)
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# All of the bonds on a certain exchange are designated by a 3

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Re: All of the bonds on a certain exchange are designated by a 3 [#permalink]

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13 Apr 2013, 07:39
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rakeshd347 wrote:
All of the bonds on a certain exchange are designated by a 3-letter, a 4-letter, or a 5-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different bonds that can be designate with these codes?

(A) 26(26^3 + 26^4)
(B) 26(26^3 + 26^5)
(C) 27(26^3 + 26^5)
(D) 27(26^3) + 26^5
(E) 26^3 + 27(26^5)

3-letter codes = 26^3;
4-letter codes = 26^4;
5-letter codes = 26^5;

Total = 26^3 + 26^4 + 26^5 = 26^3(1+26) + 26^5 = 26^3*27 + 26^5.

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[Reveal] Spoiler: OA

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Re: All of the bonds on a certain exchange are designated by a 3 [#permalink]

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12 Feb 2014, 07:03
shouldn't the question mention if the alphabets can be repeated or not? OR do we need to deduce it from the question stem?
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Re: All of the bonds on a certain exchange are designated by a 3 [#permalink]

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12 Feb 2014, 07:49
ankur1901 wrote:
shouldn't the question mention if the alphabets can be repeated or not? OR do we need to deduce it from the question stem?

If the codes were to be created by only distinct letters it would be mentioned.
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Re: All of the bonds on a certain exchange are designated by a 3 [#permalink]

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15 Aug 2015, 02:37
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Re: All of the bonds on a certain exchange are designated by a 3 [#permalink]

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14 Nov 2016, 17:33
Bunuel wrote:
rakeshd347 wrote:
All of the bonds on a certain exchange are designated by a 3-letter, a 4-letter, or a 5-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different bonds that can be designate with these codes?

(A) 26(26^3 + 26^4)
(B) 26(26^3 + 26^5)
(C) 27(26^3 + 26^5)
(D) 27(26^3) + 26^5
(E) 26^3 + 27(26^5)

3-letter codes = 26^3;
4-letter codes = 26^4;
5-letter codes = 26^5;

Total = 26^3 + 26^4 + 26^5 = 26^3(1+26) + 26^5 = 26^3*27 + 26^5.

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all-of-the-stocks-on-the-over-the-counter-market-are-126630.html
if-a-code-word-is-defined-to-be-a-sequence-of-different-126652.html
the-simplastic-language-has-only-2-unique-values-and-105845.html
a-4-letter-code-word-consists-of-letters-a-b-and-c-if-the-59065.html
a-certain-stock-exchange-designates-each-stock-with-a-86656.html
a-5-digit-code-consists-of-one-number-digit-chosen-from-132263.html
a-company-that-ships-boxes-to-a-total-of-12-distribution-95946.html

P.S. Please check the question and the answer choices when posting. Also, please name and tag the questions properly.

Hi Bunuel,

Please could you explain the formula that you have used here.

Thanks.
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Re: All of the bonds on a certain exchange are designated by a 3 [#permalink]

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27 Nov 2016, 04:45
Bunuel wrote:
rakeshd347 wrote:
All of the bonds on a certain exchange are designated by a 3-letter, a 4-letter, or a 5-letter code that is created by using the 26 letters of the alphabet. Which of the following gives the maximum number of different bonds that can be designate with these codes?

(A) 26(26^3 + 26^4)
(B) 26(26^3 + 26^5)
(C) 27(26^3 + 26^5)
(D) 27(26^3) + 26^5
(E) 26^3 + 27(26^5)

3-letter codes = 26^3;
4-letter codes = 26^4;
5-letter codes = 26^5;

Total = 26^3 + 26^4 + 26^5 = 26^3(1+26) + 26^5 = 26^3*27 + 26^5.

Similar questions to practice:
all-of-the-stocks-on-the-over-the-counter-market-are-126630.html
if-a-code-word-is-defined-to-be-a-sequence-of-different-126652.html
the-simplastic-language-has-only-2-unique-values-and-105845.html
a-4-letter-code-word-consists-of-letters-a-b-and-c-if-the-59065.html
a-certain-stock-exchange-designates-each-stock-with-a-86656.html
a-5-digit-code-consists-of-one-number-digit-chosen-from-132263.html
a-company-that-ships-boxes-to-a-total-of-12-distribution-95946.html

P.S. Please check the question and the answer choices when posting. Also, please name and tag the questions properly.

Can somebody please explain the formula used here ?
Re: All of the bonds on a certain exchange are designated by a 3   [#permalink] 27 Nov 2016, 04:45
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