Re: All of the members of club Y are either Democrats or
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Updated on: 15 Sep 2013, 05:51
You have solved the ratio for M:F in Republicans. Where did you get 30:29 from?
The question asks for M:F in Club Y, which is Republicans + Democrats. The question provides 4 categories, which can be referred to as MD, MR, FD and FR. Each member is a whole number because you can't have half a member in any category, so FD + FR is a multiple of 5 and that MD + MR is a multiple of 2. The question also states that FD > FR, and that MD = MR.
Statement 1: M = F + 1, or MD + MR = FD + (FR + 1).
If FD + FR = 5, then MR + MD = 6. This satisfies the information given, where FR = 2 and MD = 3.
If FD + FR = 10, then MR + MD = 11. This breaks with the information that MR + MD is divisible by 2.
If FD + FR = 15, then MR + MD = 16. This satisfies the information given, where FR = 6 and MD = 8.
Insufficient, but there is more information. Rearranging statement 1 gives MD - FD = FR + 1 - MR, or D = R + 1. In other words the ratio of M:F is equal to the ratio of D:R.
If FD = 3, FR =2 then MD = 3, MR = 3. D = 5, R = 6. This satisfies the information given.
If FD + FR = 15, then FD = 9 and FR = 6 and MD = 8 and MR =8. This means D = 17, R = 14. This breaks with the information that D = R + 1.
Therefore Statement 1 is sufficient to deduce the ratio of M:F is 6:5, no?
Originally posted by
stormbind on 14 Sep 2013, 07:04.
Last edited by
stormbind on 15 Sep 2013, 05:51, edited 10 times in total.