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# All the employees in a company are more than 20 years old.

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Senior Manager
Joined: 08 Aug 2005
Posts: 251
Followers: 1

Kudos [?]: 17 [0], given: 0

All the employees in a company are more than 20 years old. [#permalink]  09 Aug 2006, 03:01
All the employees in a company are more than 20 years old. Is the average of all employees more than 35?

1) 50% of employees are more than 40 years old
2) 25% of employees are more than 60 years old
Manager
Joined: 12 Feb 2006
Posts: 115
Followers: 1

Kudos [?]: 26 [0], given: 0

I'm getting C, but I just did the calculation in my head so I am probably wrong.
VP
Joined: 14 May 2006
Posts: 1418
Followers: 4

Kudos [?]: 59 [0], given: 0

st-ts on their own definitely don't work

and I am getting C

for 1000 employees total:

(500*41+250*61+250*21)/1000=41
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 121 [0], given: 0

C

Let total employees = x
Taking the worst case.

St1: Mean = (40x/2 + 20x/2)/x = 30: INSUFF

St2: Mean = (60x/4 + 20*3x/4)/x = 30: INSUFF

Combined:
Mean = (40x/2+60x/4 + 20x/4) = 20+15+5 = 40. : SUFF
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Senior Manager
Joined: 14 Jul 2005
Posts: 402
Followers: 1

Kudos [?]: 12 [0], given: 0

I am getting C also

50% > 40 and 25% > 60

My question is can the 50%>40 include the above 60 years too ?

Let us say just 4 employees are there

1 > 60 => 61
2 > 40 => 41 + (61 from above)

The other 2 employees are 21 & 21

Hence average (21 + 21 + 41 + 61) /4 = 144/4 = 36

Hence C
Manager
Joined: 26 Jun 2006
Posts: 152
Followers: 1

Kudos [?]: 1 [0], given: 0

The mean would be te smallest if we pick ages that are the smallest possible, i.e. 21, 41, and 61

ST1. (41n+21n)/(2n) = 31 (Clearly NS)
ST2. (61n+21*3n)/(4n) = 31 (Clearly NS)

ST1 & ST2

The min mean is achieved at

(61n+41n+21*2n)/(4n) = 36 > 35 (So, SUFF)
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