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# Allen travelled in a car and David travelled in a train. If

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Intern
Joined: 31 May 2006
Posts: 44
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Allen travelled in a car and David travelled in a train. If [#permalink]  22 Jul 2006, 14:58
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Allen travelled in a car and David travelled in a train. If Allen and David travelled the same length of time and Allen travelled 108 miles, how many miles did David travel?

i) Allen's average speed was 3/5 of David's average speed.
ii) Allen and David each travelled 3 hours.
Director
Joined: 06 May 2006
Posts: 781
Followers: 3

Kudos [?]: 17 [0], given: 0

A?

#1. Since we know the time travelled is the same and ratios of average speed, we know distance travelled by David.

#2. Not sufficient.
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 18

Kudos [?]: 127 [0], given: 0

Straight A

108/A = x/D
St1: A = 3D/5
108/(3D/5) = x/D
x = 180
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

SVP
Joined: 30 Mar 2006
Posts: 1738
Followers: 1

Kudos [?]: 46 [0], given: 0

A

1) Let time be t. Distance travelled by David be x

Hence
108/t = 3/5 * x/t
X = 108*5/3

Suff

2) we know the time David travelled. No idea about speed. Hence Not suff
Manager
Joined: 14 Mar 2006
Posts: 209
Followers: 1

Kudos [?]: 4 [0], given: 0

A aswell.

from stmt 1) we know the ratio of the avg speed, and since the time is the same we can solve.
from stmt2) we are given the time, but we still don't know the avg speed for david.
VP
Joined: 02 Jun 2006
Posts: 1267
Followers: 2

Kudos [?]: 43 [0], given: 0

Let
Ta = Allen's travel time
Td = David's travel time
Sa = Allen's average speed
Sd = David's average speed
Da = Allen's distance
Dd = David's distance

Given Ta = Td, Da= 108

Dist = speed x time
Dd = Sd x Td = Sd x Ta = Sdx 108/Sa

Dd = 108 x (Sd/Sa)

S1: Given Sa/Sd = 3/5
Sufficient to compute Dd.

S2: Ta = Td = 3 hrs.

Not sufficient.

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