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Although this bottle is labeled "vinegar", no frizzing

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Manager
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Although this bottle is labeled "vinegar", no frizzing [#permalink] New post 05 Apr 2006, 02:01
00:00
A
B
C
D
E

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0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Although this bottle is labeled "vinegar", no frizzing occurred when some of the liquid in it was added to powder from this box labeled "baking soda". But when an acidic liquid such as vinegar is added to baking soda the resulting mixture fizzes, so this bottle clearly has been mislabeled.

A flaw in the reasoning in the argument above is that this argument

(A) ignores the possibility that the bottle contained an acidic liquid other than vinegar.
(B) fails to exclude an alternative explanation for the observed effect.
(C) depends on the use of the imprecise term "fizz".
(D) does not take into account the fact that scientific principles can be definitively tested only under controlled laboratory conditions.
(E) assumes that the fact of labeling error is proof of an intention to deceive.

Please explain your reasoning. :-D
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 [#permalink] New post 05 Apr 2006, 02:35
I think it is B.

But I am quite confused. If B said, fails to INCLUDE an alternative expression, then it would have been perfect as it does not consider the option that the powder can be something other than baking soda. It blames only the bottle.
But B says EXCLUDE. That is a liitle confusing. But will the test catch on things like this?
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 [#permalink] New post 05 Apr 2006, 05:34
I was caught between B and C. I chose C because B said 'exclude', not 'include'. Is there a typo in B?
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 [#permalink] New post 05 Apr 2006, 07:21
B is correct. It fails to exclude the possibility that the box was labeled incorrectly.
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 [#permalink] New post 05 Apr 2006, 08:53
There is no Typo. The best answer is B.
As explained by jcgoodchild, the argument fails to "exclude" the possibility that the bottle was mislabeled. In other words, this "fact" is needed to make the conclusion stronger.

I think this is a tricky one.
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 [#permalink] New post 05 Apr 2006, 08:55
agree B.

jcgoodchild wrote:
B is correct. It fails to exclude the possibility that the box was labeled incorrectly.
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 [#permalink] New post 06 Apr 2006, 00:40
C/D/E - can be eliminated.
If A were to be true then the conclusion is correct
POE - B
  [#permalink] 06 Apr 2006, 00:40
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Although this bottle is labeled "vinegar", no frizzing

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