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Among Akova, Binova and Celeste, who got the highest share

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qhoc0010
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Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   20 Jan 2005, 13:16
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A
B
C
D
E

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Among Akova, Binova and Celeste, who got the highest share of profit?
(I) Celeste got half as much profit as Akova and Binova together.
(II) Akova got half as much profit as Binova and Celeste together got.



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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   Updated on: 20 Jan 2005, 13:37
b and c got equal shares...both less than a. am i correct?

Originally posted by Dr_Friedrich on 20 Jan 2005, 13:31.
Last edited by Dr_Friedrich on 20 Jan 2005, 13:37, edited 2 times in total.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   Updated on: 20 Jan 2005, 13:38
C is my final answer...both statements required.

Originally posted by Dr_Friedrich on 20 Jan 2005, 13:34.
Last edited by Dr_Friedrich on 20 Jan 2005, 13:38, edited 1 time in total.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   20 Jan 2005, 13:59
Can you explain a little? Sorry but I'm so bad in maths :oops but I'm studying and I'm optimistic :cool

thanks,
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   20 Jan 2005, 14:30
salut jasmine, i am waiting to see the original answer. if i am right, i will be happy to post the explantion in detail.
f.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   20 Jan 2005, 14:34
"C".

Using both the statements, each has equal share of profit .....so C is the ans.

Let PA, PB and PC be the profits.

PC = 1/2(PA+PB)...from 1st statement...insuff

PA = 1/2(PB+PC)....from 2nd statement...insuff

Combine

PC = PB....put this in first eq.....u get PA = PC....so all equal.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   21 Jan 2005, 13:52
Can you please show in detail how you find PB = PC , from these two statements.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   21 Jan 2005, 13:59
c=1/2(a+b)
a=1/2(b+c)

Add them up, you get a+c=1/2(a+c)+b
=>b=1/2(a+c)

From here you should notice the nice symetry and get the conclusion that they must be the same. However if you still want to solve it:

b=1/2(1/2b+1/2c+c)=1/4b+3/4c
=>3/4b=3/4c
=>b=c

You can get a=b similarly.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   21 Jan 2005, 15:01
My answer is C.
From both together you get A=B=C. So they all got the same amount of shares.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   21 Jan 2005, 15:28
I wonder if the correct answer must be (E)?? Even though OA is (C)

However, the question asked who got the highest. The answer is Akova, Binova and Celeste (since all equal). There are 3 answers. Just as we say (E) if x = 5 or x = 3

Please give me your oppinion.
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   21 Jan 2005, 22:45
If the answer is all the three, then I think E will be right as we can't give a single answer.
Good one to remember!
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   21 Jan 2005, 22:55
E means I plus II don't give sufficient information about who has the highest profit. However I and II together IS sufficient (as no other information will be needed to get to the answer), even if the answer is nobody has a higher profit than others.

In other words, correct answer for this question is still (C).
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   22 Jan 2005, 06:00
In DS problem, if we combine (1) and (2) and sure we cannot find x, can we say it is (C), since x cannot be found, and that is the answer???

Same as this one??
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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink] New post   22 Jan 2005, 06:35
Its (C). took some time though.



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Re: Among Akova, Binova and Celeste, who got the highest share [#permalink]
22 Jan 2005, 06:35
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