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09 Sep 2007, 15:13
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| Amount earned per day| $96 |$84 | $80 |$70 | $48 | ____________________________________________ | Number of Days | 4 | 7 | 4 | 3 | 2 | _____________________________________________ A student worked for 20 days. For each of the amounts shown in the first row of the table, the second row gives the number of days that the student earned that amount. What is the median amount of money that the student earned per day for the 20 days? 1.$96
2. $84 3.$80
4. $70 5.$48

- Brajesh
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09 Sep 2007, 20:31
guys..please show working..is there a quick way to do these type of problems...i cant possibly thnk you would actually add the numbers up and divide by 20??
Current Student
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09 Sep 2007, 20:40
my quick way of doing this..

4(96)+7(84)+4(80)+3(70)+2(48)

4(96+80)+7(84)+3(70)

so i basically list the numbers by their frequency

70 70 70 80 80 80 80 84......84(7 times) 96 96 96 96

clearly the median has to be the middle two numbers, which are 84 and 84

(84+84)/2=84

84 is the answer...

took about 22 secs
Director
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09 Sep 2007, 20:56
fresinha12 wrote:
guys..please show working..is there a quick way to do these type of problems...i cant possibly thnk you would actually add the numbers up and divide by 20??

= (20+1)/2 =10.5

so the average between the values of 10th day and 11th day is the median.
10th day value = 84
11th day value = 84
so average of these two = 84

its so quick. took less than 10 sec.
Senior Manager
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09 Sep 2007, 21:39
The quickest way to solve it, in my opinion, shown by Fistail. Though you have to order the numbers viusally, I mean just count which is 10.5 in row.

Ans: B:84
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09 Sep 2007, 21:45
Since we have even number of elements (days), the median is the mean of the 10th and 11th element. From the chart, we know this is $84 since both 10th and 11th element is$84.
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10 Sep 2007, 05:21
OA is B.

Thanks,
Brajesh
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10 Sep 2007, 06:13
Median of a list of numbers is the mid point.

Median = 84
10 Sep 2007, 06:13
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