Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

22 Jun 2011, 06:02

2

This post received KUDOS

4

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

69% (04:07) correct
31% (02:44) wrong based on 217 sessions

HideShow timer Statistics

Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 15 for which Amy's becomes an equal or better deal?

A 24 B 25 C 26 D 27 E 28

I know we can solve this question by solving 20x + (y - 20)(.8)x = 14x + (y - 14)(.9)x

Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 15 for which Amy's becomes an equal or better deal?

A 24 B 25 C 26 D 27 E 28

I know we can solve this question by solving 20x + (y - 20)(.8)x = 14x + (y - 14)(.9)x

Is there a better way to do this quickly?

i think plugging in can be an option but I guess algebra is best for this question.

Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 15 for which Amy's becomes an equal or better deal?

A 24 B 25 C 26 D 27 E 28

I know we can solve this question by solving 20x + (y - 20)(.8)x = 14x + (y - 14)(.9)x

Is there a better way to do this quickly?

If I follow the wordings of the question, the answer should be 11.

If the question were: "What is the minimum number of pounds for which Amy's becomes an equal or better deal" 26 lbs would be the answer.

Equation: 20+(k-5)0.8=14+(k+1)0.9

Alternative approach can be substitution. Is it better, don't know!!!
_________________

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

28 Jun 2013, 07:05

fozzzy wrote:

Would plugin be a better strategy for this question or the algebraic approach

My personal opinion? No

A 24 B 25 C 26 D 27 E 28

The answer choices are too close, number picking works best when the choices are more different. If you cannot set up an equation, plug numbers and see what you find, but I would not consider it a good strategy here.

My opinion
_________________

It is beyond a doubt that all our knowledge that begins with experience.

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

28 Jun 2013, 07:55

7

This post received KUDOS

1

This post was BOOKMARKED

udaymathapati wrote:

Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 15 for which Amy's becomes an equal or better deal?

A 24 B 25 C 26 D 27 E 28 I know we can solve this question by solving 20x + (y - 20)(.8)x = 14x + (y - 14)(.9)x

Is there a better way to do this quickly?

fozzzy wrote:

Would plugin be a better strategy for this question or the algebraic approach

The given values in the problem can help one do this problem logically, without the aid of any equations/pluggin-in:

Till 14 pounds, both Amy and Lucia would sell at 1 dollar each. After this, for each pound, Lucia offers a discount of 0.1 dollars as compared to the price offered by Amy. Thus, a person buying from both would have saved 0.6 dollars for 20 pounds with respect to Lucia.

After 20 pounds, for each pound, Amy offers a discount of 0.1 dollars as compared to the price offered by Lucia. Thus, to offset the initial discount of 0.6 dollars from Lucia, the person should buy atleast 6 more pounds, to exactly equalize the offered price between Amy and Lucia.

Thus the minimum pounds required to exactly match the price is 20+6 = 26 pounds.
_________________

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

28 Jun 2013, 08:17

3

This post received KUDOS

2

This post was BOOKMARKED

udaymathapati wrote:

Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 15 for which Amy's becomes an equal or better deal?

A 24 B 25 C 26 D 27 E 28

I know we can solve this question by solving 20x + (y - 20)(.8)x = 14x + (y - 14)(.9)x

Is there a better way to do this quickly?

For Amy's deal to be better, the cost has to be less or equal to Lucia's

Assuming 'n' is the number of pounds of kale, the equation is

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

18 Nov 2013, 16:52

I think simple logic will do the trick here,

From 15th to 20th pound Lucia loses 0.1S to Amy, therefore she is basically 0.6$ behind Amy when Amy starts her sale. When Amy starts her Sale she loses 0.1$ to Lucia, therefore, Lucia will Cover the 0.6$ when Amy has sold 6 pounds of the stuff. i.e. 20+6 =26

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

19 Nov 2013, 19:14

udaymathapati wrote:

Amy's sells kale at x dollar per pound for the first 20 pounds and .8x for every subsequent pound. Lucia's price is x per pound for the first 14 pounds and .9x for subsequent pounds. What is the minimum number of pounds over 15 for which Amy's becomes an equal or better deal?

A 24 B 25 C 26 D 27 E 28

I know we can solve this question by solving 20x + (y - 20)(.8)x = 14x + (y - 14)(.9)x

Is there a better way to do this quickly?

Since the Amy's deal need to be equal/ better it not possible for the first 20 pounds . Hence calculate the Lucia deal for first 20 pounds which comes to be 19.4 x. Now the difference of margin between the two deals is 20x-19.4x = 0.6x. Now the difference between above 20 pounds for both is 0.9 x -0.8 x = 0.1 x. So to cover the 0.6 x we will have to purchase 0.6x/0.1x= 6 more pounds. Hence the answer is 6.
_________________

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

16 Feb 2015, 14:57

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: Amy's sells kale at x dollar per pound for the first 20 poun [#permalink]

Show Tags

05 Oct 2016, 06:28

did the straightforward way... 20x+0.8x(y-20)=14x+0.9x(y-14) we can factor out x from both sides then divide by x. 6=0.9y - 63/5 - 0.8y +16 63/5 = 12.6 6=0.1y + 3.4 2.6 = 0.1y y=26. so when we have 26 pounds, Amy's deal is the same as Lucia's. If we buy more from Amy, we'll save more...

gmatclubot

Re: Amy's sells kale at x dollar per pound for the first 20 poun
[#permalink]
05 Oct 2016, 06:28

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Since my last post, I’ve got the interview decisions for the other two business schools I applied to: Denied by Wharton and Invited to Interview with Stanford. It all...