Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

An alchemist discovered that the formula to turn ordinary me [#permalink]
30 Dec 2012, 09:20

2

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

35% (medium)

Question Stats:

68% (02:55) correct
32% (01:49) wrong based on 85 sessions

An alchemist discovered that the formula to turn ordinary metal into gold is \(G = \frac{3}{2}M + 15\), where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
30 Dec 2012, 11:15

1

This post received KUDOS

best approach would be to plug in answer choices.

start with C: M=22.5 2M=45 G = 22.5*3/2+15 as it would have a fractional part.. skip it choose a number which wont result in fractional part so A and D remains

Take D: M=30 2M=60 which should be our target value

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
09 Jan 2013, 06:36

mansoorfarooqui wrote:

best approach would be to plug in answer choices.

start with C: M=22.5 2M=45 G = 22.5*3/2+15 as it would have a fractional part.. skip it choose a number which wont result in fractional part so A and D remains

Take D: M=30 2M=60 which should be our target value

put M=30 we get G=60 so D is the answer

PS:Please consider kudos if it was helpful

Hey Mansoor, "a metal bar weighs twice as much as a gold bar" this doesnt mean M=2G ? _________________

GMAT - Practice, Patience, Persistence Kudos if u like

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
09 Jan 2013, 07:07

1

This post received KUDOS

Expert's post

danzig wrote:

An alchemist discovered that the formula to turn ordinary metal into gold is \(G = \frac{3}{2}M + 15\), where G is the number of gold bars and M is the number of metal bars. If a metal bar weighs twice as much as a gold bar, how many metal bars will yield an equal weight of gold?

A. 10 B. 15 C. 22.5 D. 30 E. 67.5

A time saving method: Since we know that \(Integer+Integer=Integer\), and number of bars can't be in fractional form, therefore \(3M/2\) must be an integer or M must be a multiple of 2. The only options that we have is A and D. On putting 10 and 30 respectively, we find that 30 fits the conditions. Hence 30 is the answer. _________________

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
10 Jan 2013, 10:38

Rock750 wrote:

Since a metal bar weighs twice as much as a gold bar, 2M = G

Thus, by the equation given : 2M = (3/2 *M) + 15 M/2 = 15

M = 30

Hence,

Answer : D

Well here i faced confusion, i thought if 1 bar of mettal is twice havier than 1 bar of gold, for example 1 bar of M=4 kg then 1 bar of G=2 kg, that means 4=2*2 --> M=2G but not 2M=G, So according to my initial calculation i stuck then i decided to plug in and found D plausable.

But could anyone suggest whether my initial thinking was wrong? _________________

If you found my post useful and/or interesting - you are welcome to give kudos!

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
10 Jan 2013, 14:17

ziko wrote:

Rock750 wrote:

Since a metal bar weighs twice as much as a gold bar, 2M = G

Thus, by the equation given : 2M = (3/2 *M) + 15 M/2 = 15

M = 30

Hence,

Answer : D

Well here i faced confusion, i thought if 1 bar of mettal is twice havier than 1 bar of gold, for example 1 bar of M=4 kg then 1 bar of G=2 kg, that means 4=2*2 --> M=2G but not 2M=G, So according to my initial calculation i stuck then i decided to plug in and found D plausable.

But could anyone suggest whether my initial thinking was wrong?

Did u get D using M=2G ? _________________

KUDOS is the good manner to help the entire community.

"If you don't change your life, your life will change you"

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
11 Jan 2013, 02:14

Rock750 wrote:

ziko wrote:

Rock750 wrote:

Since a metal bar weighs twice as much as a gold bar, 2M = G

Thus, by the equation given : 2M = (3/2 *M) + 15 M/2 = 15

M = 30

Hence,

Answer : D

Well here i faced confusion, i thought if 1 bar of mettal is twice havier than 1 bar of gold, for example 1 bar of M=4 kg then 1 bar of G=2 kg, that means 4=2*2 --> M=2G but not 2M=G, So according to my initial calculation i stuck then i decided to plug in and found D plausable.

But could anyone suggest whether my initial thinking was wrong?

Did u get D using M=2G ?

No i did not, that s why i raised this question, to clarify where i did wrong? or where exactly i am loosing the track. _________________

If you found my post useful and/or interesting - you are welcome to give kudos!

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
11 Jan 2013, 04:31

Expert's post

1

This post was BOOKMARKED

ziko wrote:

Rock750 wrote:

Since a metal bar weighs twice as much as a gold bar, 2M = G

Thus, by the equation given : 2M = (3/2 *M) + 15 M/2 = 15

M = 30

Hence,

Answer : D

Well here i faced confusion, i thought if 1 bar of mettal is twice havier than 1 bar of gold, for example 1 bar of M=4 kg then 1 bar of G=2 kg, that means 4=2*2 --> M=2G but not 2M=G, So according to my initial calculation i stuck then i decided to plug in and found D plausable.

But could anyone suggest whether my initial thinking was wrong?

Notice that M is the number of metal bars (not their weight) And G is the number of gold bars.

If weight of a metal bar is twice the weight of a gold bar, and if you want to equate their weights, you will need twice the number of gold bars to make their weights equal.

That is how you get 2M = G (Number of gold bars should be twice the number of metal bars) _________________

Re: An alchemist discovered that the formula to turn ordinary me [#permalink]
22 Jun 2015, 04:36

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

MBA Acceptance Rate by Country Most top American business schools brag about how internationally diverse they are. Although American business schools try to make sure they have students from...

McCombs Acceptance Rate Analysis McCombs School of Business is a top MBA program and part of University of Texas Austin. The full-time program is small; the class of 2017...